Height Checker
A school is trying to take an annual photo of all the students. The students are asked to stand in a single file line in non-decreasing order by height. Let this ordering be represented by the integer array expected where expected[i] is the expected height of the ith student in line.
You are given an integer array heights representing the current order that the students are standing in. Each heights[i] is the height of the ith student in line (0-indexed).
Return the number of indices where heights[i] != expected[i].
Example 1:
Input: heights = [1,1,4,2,1,3]
Output: 3
Explanation:
heights: [1,1,4,2,1,3]
expected: [1,1,1,2,3,4]
Indices 2, 4, and 5 do not match.
Example 2:
Input: heights = [5,1,2,3,4]
Output: 5
Explanation:
heights: [5,1,2,3,4]
expected: [1,2,3,4,5]
All indices do not match.
Example 3:
Input: heights = [1,2,3,4,5]
Output: 0
Explanation:
heights: [1,2,3,4,5]
expected: [1,2,3,4,5]
All indices match.
Constraints:
1 <= heights.length <= 100
1 <= heights[i] <= 100
思路一:复制一份数组,先排序,后对比
public int heightChecker(int[] heights) {
int[] temp = new int[heights.length];
System.arraycopy(heights, 0, temp, 0, heights.length);
Arrays.sort(temp);
int count = 0;
for (int i = 0; i < heights.length; i++) {
if (temp[i] != heights[i]) {
count++;
}
}
return count;
}
标签:1051,temp,int,heights,easy,expected,Output,height,leetcode
From: https://www.cnblogs.com/iyiluo/p/17124769.html