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JS逆向入门篇1

时间:2022-09-02 22:46:50浏览次数:73  
标签:c3 逆向 url base64DecodeChars len JS 入门篇 var out

目标网站:https://ac.scmor.com/

第一步 点击关键字

image
visit('U3kwBQctIQAjMHZdVC1xRDs5LVQqURUfKxwQGjQACBZ5VysGVytwfmVgDQBVKSMZYRpbGwxAFhYOKl5JAWZRDw4EXzwWBwMT')

第二步 在控制台输入visit定位image

第三步 观察并且下断点

发现存在传入url的函数,发现可疑的加密函数!

补充知识点 单步跟踪和多行跳image

image

最关键一步 扣js代码--缺啥补啥image

缺base64decode

image

缺base64DecodeChars

image

缺Gword 这个特殊需要写死

image
image
image

成功了

image

中间遇到了一个错误

image
这个错误是由于被调用函数放在最后,调用时找不到该函数,需要把base64DecodeChars函数放在前面

爬取多个网站

image
发现 autourl这个变量,我们继续去断点那看是如何调用的 扣下来
image

然后修改下输出 把输出图片去掉 我们只要url 最后调用
image

最终效果image

参考代码

点击查看代码
<!DOCTYPE html>
<html>
	<head>
		<meta charset="utf-8">
		<title></title>
	</head>
	<body>
		<script type="text/javascript">
			function strdecode(string) {
			 string = base64decode(string);
			 key = Gword + hn;
			 len = key.length;
			 code = '';
			 for (i = 0; i < string.length; i++) {
			 var k = i % len;
			 code += String.fromCharCode(string.charCodeAt(i) ^ key.charCodeAt(k));
			 }
			 return base64decode(code);
			}
			
			
			var base64DecodeChars = new Array(-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,62,-1,-1,-1,63,52,53,54,55,56,57,58,59,60,61,-1,-1,-1,-1,-1,-1,-1,0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,-1,-1,-1,-1,-1,-1,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,-1,-1,-1,-1,-1);
			var Gword = '21b5del6oIO57e01a'
			var hn = 'ac.scmor.com'
			//输出至控制台看看缺啥
			//console.log(strdecode('U3kwBQctIQAjMHZdVC1xRDs5LVQqURUfKxwQGjQACBZ5VysGVytwfmVgDQBVKSMZYRpbGwxAFhYOKl5JAWZRDw4EXzwWBwMT'));
			var autourl=["ZAM0RgYmLl0Ne3pZfjZxATgbMlcpJD8HKEMyGDdlfBVsMDcBbzgAf2xjJEhoDDBWYBkAFyE1eAghLA8M","U3kwBQctIQAjMHZdVC1xRDs5LVQqURUfKxwQGjQACBZ5VysGVytwfmVgDQBVKSMZYRpbGwxAFhYOKl5JAWZRDw4EXzwWBwMT","U3kwBQctIQAjMHZPbldbRQApNUc/DlQWKFdWBQ9bCV8=","U3kwBQctIQAjMHZPbhwFRjg2VkUqNyAWP31WBQ8AARQ=","U3kwBQctIQAjMHYGU1ZTRAMmD0cQDisWF31WBzRLBAhXDV1R","U3kwBQctIQAjMHYGU1ZTRAJTLV4pJFRcEEdWBQ9bCAxXHV1R","U3kwBQctIQAjMHZebTJmRgJTNUYQDiMAPkMtBSFFDF8=","U3kwBQctIQAjMHYBVBwFQgJSJR0RIFgZEUMAGQ==","U3kwBQctIQAjMHZPbldYRwMmJVc/DhUHEEM5Bw9cfw1RN1AGVAZxcg=="]
			
			function run() {
			    for (var i = 1; i < autourl.length; i++) {
			        url = autourl[i];
			        if (Gword != '')
			            url = strdecode(url);
			        var st = url.indexOf("//", 1);
			        var _domain = url.substring(st + 1, url.length);
			        var et = _domain.indexOf("/", 1);
			        surl = url.substring(0, et + st + 2);
			        document.write(url+'<br/>');   //<br/> == c语言中的\n
			    }
			}
			
			//调用输出的函数
			run()
			
			function base64decode(str) {
			    var c1, c2, c3, c4;
			    var i, len, out;
			    len = str.length;
			    i = 0;
			    out = "";
			    while (i < len) {
			        do {
			            c1 = base64DecodeChars[str.charCodeAt(i++) & 0xff];
			        } while (i < len && c1 == -1);
			        if (c1 == -1)
			            break;
			        do {
			            c2 = base64DecodeChars[str.charCodeAt(i++) & 0xff];
			        } while (i < len && c2 == -1);
			        if (c2 == -1)
			            break;
			        out += String.fromCharCode((c1 << 2) | ((c2 & 0x30) >> 4));
			        do {
			            c3 = str.charCodeAt(i++) & 0xff;
			            if (c3 == 61)
			                return out;
			            c3 = base64DecodeChars[c3];
			        } while (i < len && c3 == -1);
			        if (c3 == -1)
			            break;
			        out += String.fromCharCode(((c2 & 0XF) << 4) | ((c3 & 0x3C) >> 2));
			        do {
			            c4 = str.charCodeAt(i++) & 0xff;
			            if (c4 == 61)
			                return out;
			            c4 = base64DecodeChars[c4];
			        } while (i < len && c4 == -1);
			        if (c4 == -1)
			            break;
			        out += String.fromCharCode(((c3 & 0x03) << 6) | c4);
			    }
			    return out;
			}
			
			
		</script>
	</body>
</html>

标签:c3,逆向,url,base64DecodeChars,len,JS,入门篇,var,out
From: https://www.cnblogs.com/fengxi110/p/16651561.html

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