获取第一行内容

内容如下

$ lscpu
Architecture:            x86_64
  CPU op-mode(s):        32-bit, 64-bit
  Address sizes:         39 bits physical, 48 bits virtual
  Byte Order:            Little Endian
CPU(s):                  8
  On-line CPU(s) list:   0-7
Vendor ID:               GenuineIntel
  Model name:            11th Gen Intel(R) Core(TM) i5-1135G7 @ 2.40GHz
    CPU family:          6
    Model:               140
    Thread(s) per core:  2
    Core(s) per socket:  4
    Socket(s):           1
    Stepping:            1
    CPU(s) scaling MHz:  59%
    CPU max MHz:         4200.0000
    CPU min MHz:         400.0000
    BogoMIPS:            4838.40

想获取第一行cpu架构，命令如下

$ lscpu|awk 'NR==1{print $0}'
Architecture:                    x86_64

NR是用来匹配第几行内容，NR==1表示第一行，print \$0是把整行输出。默认awk是空格分隔，所以如果是print \$1，就输出Architecture，如果是\$2就输出x86_64，如下

$ lscpu|awk 'NR==1{print $2}'
x86_64