第四次限时训练题目大意及ac代码

Atilla's Favorite Problem

题目大意

accode

#include <bits/stdc++.h>
#define int long long

using namespace std;

signed main()
{
    ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);

    int T;
    cin >> T;
    while (T--)
    {
        int n;
        cin >> n;
        string s;
        cin >> s;
        int x = 0;
        for (int i = 0; i < s.size(); i++)
        {
            int t = s[i] - 'a' + 1;
            x = max(t, x);
        }
        cout << x << "\n"

Minimum Varied Number

题目大意

accode

#include <bits/stdc++.h>
#define int long long

using namespace std;

int a[50];
int n;

signed main()
{
    ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);

    int T;
    cin >> T;
    while (T--)
    {
        cin >> n;
        for (int i = 1; i <= 40; i++)
            a[i] = 0;
        int x = 9;
        int k = 1;
        while (n)
        {
            if (n >= x)
            {
                n -= x;
                a[k] = x;
                x--;
                k++;
            }
            else
                x--;
        }
        for (int i = k - 1; i >= 1; i--)
            cout << a[i];
        cout << "\n";
    }
    return 0;
}

Brain's Photos

题目大意

accode

#include <fstream>
#include <iostream>
#include <stdlib.h>
#include <vector>
#include <string>
using namespace std;
const int N = 20;

int main()
{
    int n, m;
    cin >> n >> m;
    getchar();
    string s[100];
    for (int i = 0; i < n; i++)
    {
        getline(cin, s[i]);
    }
    bool temp = false;
    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < s[i].size(); j++)
        {
            if (s[i][j] == 'C' || s[i][j] == 'M' || s[i][j] == 'Y')
            {
                temp = true;
                break;
            }
        }
    }
    if (temp) cout << "#Color" << endl;
    else cout << "#Black&White" << endl;
    return 0;
}

Soldier and Bananas

题目大意

accode

#include <fstream>
#include <iostream>
#include <stdlib.h>
#include <vector>
#include <string>
using namespace std;
const int N = 20;

int main()
{
    int k, n, w;
    cin >> k >> n >> w;
    int sum = 0;
    for (int i = 1; i <= w; i++)
    {
        sum += i;
    }
    if (n >= sum * k) cout << 0 << endl;
    else cout << sum * k - n << endl;
    return 0;
}