with tbl([Name],[Class],[Score]) as( select N'张三',N'一班',648 union all select N'李四',N'一班',215 union all select N'王五',N'一班',321 union all select N'聊六',N'一班',523 union all select N'张三',N'二班',256 union all select N'李四',N'二班',512 union all select N'王五',N'二班',128 union all select N'聊六',N'二班',1024 ) --select * from ( --select [Name],[Class],rank() over(partition by [Class] order by [Score] desc) r from tbl)a --order by a.r select * from ( select [Name],[Class],dense_rank() over(partition by [Class] order by [Score] desc) r from tbl)b where b.[Class]=N'一班' order by b.r
标签:union,over,partition,rank,order,Score,Class,select From: https://www.cnblogs.com/hofmann/p/16640167.html