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1006. Sign In and Sign Out (25)

时间:2022-11-25 14:34:59浏览次数:60  
标签:tmin tmax Sign time 1006 out ID Out


1006. Sign In and Sign Out (25)


时间限制


400 ms



内存限制



65536 kB



代码长度限制



16000 B



判题程序



Standard



作者



CHEN, Yue


At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. Given the records of signing in's and out's, you are supposed to find the ones who have unlocked and locked the door on that day.

Input Specification:

Each input file contains one test case. Each case contains the records for one day. The case starts with a positive integer M, which is the total number of records, followed by M lines, each in the format:



ID_number Sign_in_time Sign_out_time



where times are given in the format HH:MM:SS, and ID number is a string with no more than 15 characters.

Output Specification:

For each test case, output in one line the ID numbers of the persons who have unlocked and locked the door on that day. The two ID numbers must be separated by one space.

Note: It is guaranteed that the records are consistent. That is, the sign in time must be earlier than the sign out time for each person, and there are no two persons sign in or out at the same moment.


Sample Input:


3
CS301111 15:30:28 17:00:10
SC3021234 08:00:00 11:25:25
CS301133 21:45:00 21:58:40


Sample Output:


SC3021234 CS301133



评测结果

时间

结果

得分

题目

语言

用时(ms)

内存(kB)

用户

7月17日

20:16

答案正确

​25​

​1006​

​C++ (g++ 4.7.2)​

1

364

​datrilla​

测试点

测试点

结果

用时(ms)

内存(kB)

得分/满分

0

答案正确

1

244

2/2

1

答案正确

1

364

4/4

2

答案正确

1

256

4/4

3

答案正确

1

364

4/4

4

答案正确

1

364

5/5

5

答案正确

1

256

6/6

#include<iostream>
#include<string>
using namespace std;
bool CompareTime(string tmax,string tmin)
{
if(tmax[0]>tmin[0])
return true;
else if(tmax[0]==tmin[0])
{
if(tmax[1]>tmin[1]) return true;
else if(tmax[1]==tmin[1])
{
if(tmax[3]>tmin[3]) return true;
else if(tmax[3]==tmin[3])
{
if(tmax[4]>tmin[4]) return true;
else if(tmax[4]==tmin[4])
{
if(tmax[6]>tmin[6]) return true;
else if(tmax[6]==tmin[6]&&tmax[7]>tmin[7])
return true;
}
}
}
}
return false;
}
int main()
{
int M;
string ID_number1,Sign_in_time,Sign_out_time,n1,t1,t2,ID_number12;
cin>>M;
cin>>ID_number1>>Sign_in_time>>Sign_out_time;
ID_number12=ID_number1;
M--;
while(M--)
{
cin>>n1>>t1>>t2;
if(CompareTime(Sign_in_time,t1))
{
Sign_in_time=t1;
ID_number1=n1;
}
if(CompareTime(t2,Sign_out_time))
{
Sign_out_time=t2;
ID_number12=n1;
}
}
cout<<ID_number1<<" "<<ID_number12<<endl;
return 0;
}


标签:tmin,tmax,Sign,time,1006,out,ID,Out
From: https://blog.51cto.com/datrilla/5886669

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