The more people you love, the weaker you are.
The things we love destroy us every time.
\(vscode\)也配置好了，\(html\)慢慢摸索着也能写些简单的本地网页了，\(CSP\)报名了，等一个小时后的两点\(N2\)也可以报名了。一切都刚刚开始，一切的一起，从结束中。太阳底下没有新鲜事，每次日出都是盛大开场
假面的小丑，上台了，不管他愿不愿意，只是履行着久远岁月最初的约定
尽管只剩他一个人记得约定
尽管步履蹒跚，跌跌撞撞
男人，就是为了一个遥远的约定不惜代价，浪漫至死的笨蛋
It's a trick, a shadow on the wall. And a very small man can cast a very large shadow.
- 归一化处理
AC代码
# include "bits/stdc++.h"
using namespace std;
int main() {
int n;
scanf("%d", &n);
vector<double> a(n + 1);
double sum = 0;
for(int i = 1; i <= n; ++i) scanf("%lf", &a[i]), sum += a[i];
double ave = sum / (double) n;
sum = 0;
for(int i = 1; i <= n; ++i) sum += (a[i] - ave) * (a[i] - ave);
double dev = sqrt(sum / (double) n);
for(int i = 1; i <= n; ++i) printf("%.16lf\n", (a[i] - ave) / dev);
return 0;
}
60分（精度问题）代码
# include "bits/stdc++.h"
using namespace std;
double a[1003];
int main() {
freopen("in.txt", "r", stdin);
int n;
scanf("%d", &n);
// vector<long double> a(n + 1);
for(int i = 1; i <= n; ++i) {
scanf("%lf", &a[i]);
}
// if(n == 1) {
// printf("0");
// return 0;
// }
double ave = accumulate(a + 1, a + n + 1, 0) / (double) (1.0 * n);
double sum = accumulate(a + 1, a + n + 1, 0, [ave](double sum, double val) {
return sum + (ave - val) * (ave - val);
});
double dev = sqrt(sum / (double) (1.0 * n));
auto calc = [&](double x) {
return (x - ave) / dev;
};
for(int i = 1; i <= n; ++i) {
printf("%.16lf\n", calc(a[i]));
}
return 0;
}
