A+B
`
考虑高精度

代码

#include<iostream>
using namespace std;
const int N = 510;
int arr[N],aa[N],ab[N];
int main(){
    string a,b;
    cin>>a;
    cin>>b;
    int sizea = a.length(),sizeb = b.length();
    int len = sizea>sizeb?sizea:sizeb;
    for(int i = a.length()-1,index=0;i>=0;i--,index++){
        aa[index] = a.at(i)-'0';
            
    }
    
    for(int i = b.length()-1,index=0;i>=0;i--,index++){
        ab[index] = b.at(i) - '0';
      
    }
    for(int i = 0;i<len;i++){
        arr[i] += aa[i]+ab[i];
        // cout<<arr[i]<<endl;
        arr[i+1]+=arr[i]/10;
        arr[i]%=10;
        
    }
    
    if(arr[len])cout<<arr[len];
    for(int i = len-1;i>=0;i--){
        cout<<arr[i];
    }
    return 0;



}