Binary Partitions
Time Limit: 2 Seconds
Memory Limit: 65536 KB
Hadi loves binary numbers. So he likes to partition everything into powers of two. He wonders in how many ways he can partition a given number n into powers of two.
For example, there are 2 ways to partition 3: 1+1+1 and 1+2.
Help Him.
Input
The first line of input consists of a single integer T, the number of test-cases. Each test-case consists of a line containing n. (0 <= n <= 2,000,000)
Output
For each test-case, output a line containing number of ways in which n can be partitioned into binary numbers modulo 1,000,000.
Sample Input
4
1
2
3
280
Sample Output
1
2
2
93298
直接当做背包搞好了
#include<cstdio>
#include<cmath>
#include<vector>
#include<cstring>
#include<algorithm>
using namespace std;
typedef long long LL;
const int maxn = 2000005;
int n, f[maxn], x;
int main()
{
f[0] = 1;
for (int j = 0; (1 << j) < maxn; j++)
for (int i = (1 << j); i < maxn; i++)
(f[i] += f[i - (1 << j)]) %= 1000000;
while (scanf("%d", &n) != EOF)
{
while (n--)
{
scanf("%d", &x);
printf("%d\n", f[x]);
}
}
return 0;
}