Find Target Indices After Sorting Array
You are given a 0-indexed integer array nums and a target element target.
A target index is an index i such that nums[i] == target.
Return a list of the target indices of nums after sorting nums in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.
Example 1:
Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.
Example 2:
Input: nums = [1,2,5,2,3], target = 3
Output: [3]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 3 is 3.
Example 3:
Input: nums = [1,2,5,2,3], target = 5
Output: [4]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 5 is 4.
思路一：对数字进行完全分类，只可能出现下面三种情况，只要统计等于和小于 target 的个数就能求出解
- 大于 target
- 等于 target
- 小于 target
public List<Integer> targetIndices(int[] nums, int target) {
int minCount = 0;
int equalCount = 0;
for (int i = 0; i < nums.length; i++) {
if (nums[i] < target) {
minCount++;
} else if (nums[i] == target) {
equalCount++;
}
}
List<Integer> list = new ArrayList<>();
for (int i = 0; i < equalCount; i++) {
list.add(minCount++);
}
return list;
}