无涯教程-MySQL IN Clause函数

您可以使用 IN 子句替换许多 OR 条件

要了解 IN 子句,请考虑一个 employee_tbl 表,该表具有以下记录-

mysql> SELECT * FROM employee_tbl;
+------+------+------------+--------------------+
|  id  | name | work_date  | daily_typing_pages |
+------+------+------------+--------------------+
|   1  | John | 2007-01-24 |        250         |
|   2  | Ram  | 2007-05-27 |        220         |
|   3  | Jack | 2007-05-06 |        170         |
|   3  | Jack | 2007-04-06 |        100         |
|   4  | Jill | 2007-04-06 |        220         |
|   5  | Zara | 2007-06-06 |        300         |
|   5  | Zara | 2007-02-06 |        350         |
+------+------+------------+--------------------+
7 rows in set (0.00 sec)

现在,假设基于上表,您要显示的daily_typing_pages分别等于250、220和170的记录。可以使用 OR 条件,如下所示

mysql>SELECT * FROM employee_tbl 
   ->WHERE daily_typing_pages= 250 OR  
   ->daily_typing_pages= 220 OR  daily_typing_pages= 170; 
+------+------+------------+--------------------+
|  id  | name | work_date  | daily_typing_pages |
+------+------+------------+--------------------+
|   1  | John | 2007-01-24 |        250         |
|   2  | Ram  | 2007-05-27 |        220         |
|   3  | Jack | 2007-05-06 |        170         |
|   4  | Jill | 2007-04-06 |        220         |
+------+------+------------+--------------------+
4 rows in set (0.02 sec)

使用 IN 子句可以实现相同的效果,如下所示-

mysql> SELECT * FROM employee_tbl 
   -> WHERE daily_typing_pages IN ( 250, 220, 170 );
+------+------+------------+--------------------+
|  id  | name | work_date  | daily_typing_pages |
+------+------+------------+--------------------+
|   1  | John | 2007-01-24 |        250         |
|   2  | Ram  | 2007-05-27 |        220         |
|   3  | Jack | 2007-05-06 |        170         |
|   4  | Jill | 2007-04-06 |        220         |
+------+------+------------+--------------------+
4 rows in set (0.02 sec)

参考链接

https://www.learnfk.com/mysql/mysql-in-clause.html