标签:right -- question 复旦大学 练题 2021 mysql device id
描述
题目: 现在运营想要了解复旦大学的每个用户在8月份练习的总题目数和回答正确的题目数情况,请取出相应明细数据,对于在8月份没有练习过的用户,答题数结果返回0.
示例:用户信息表user_profile
id |
device_id |
gender |
age |
university |
gpa |
active_days_within_30 |
1 |
2138 |
male |
21 |
北京大学 |
3.4 |
7 |
2 |
3214 |
male |
|
复旦大学 |
4.0 |
15 |
3 |
6543 |
female |
20 |
北京大学 |
3.2 |
12 |
4 |
2315 |
female |
23 |
浙江大学 |
3.6 |
5 |
5 |
5432 |
male |
25 |
山东大学 |
3.8 |
20 |
6 |
2131 |
male |
28 |
山东大学 |
3.3 |
15 |
7 |
4321 |
female |
26 |
复旦大学 |
3.6 |
9 |
示例:question_practice_detail
id |
device_id |
question_id |
result |
date |
1 |
2138 |
111 |
wrong |
2021-05-03 |
2 |
3214 |
112 |
wrong |
2021-05-09 |
3 |
3214 |
113 |
wrong |
2021-06-15 |
4 |
6543 |
111 |
right |
2021-08-13 |
5 |
2315 |
115 |
right |
2021-08-13 |
6 |
2315 |
116 |
right |
2021-08-14 |
7 |
2315 |
117 |
wrong |
2021-08-15 |
…… |
|
|
|
|
根据示例,你的查询应返回以下结果:
device_id |
university |
question_cnt |
right_question_cnt |
3214 |
复旦大学 |
3 |
0 |
4321 |
复旦大学 |
0 |
0
|
select tb1.device_id,university,count(question_id) as question_cnt,sum(if(result = 'right',1,0)) as right_question_cnt
from user_profile tb1
join question_practice_detail tb2
on tb1.device_id = tb2.device_id and month(date) = 8
where university = '复旦大学'
group by device_id
标签:right,
--,
question,
复旦大学,
练题,
2021,
mysql,
device,
id
From: https://www.cnblogs.com/xinger123/p/16734457.html