实验任务1
task1.c
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <time.h> 4 5 #define N 5 6 #define N1 397 7 #define N2 476 8 #define N3 21 9 10 int main() { 11 int cnt; 12 int random_major, random_no; 13 14 srand(time(NULL)); 15 16 cnt = 0; 17 while(cnt < N) { 18 random_major = rand() % 2; 19 20 if(random_major) { 21 random_no = rand() % (N2 - N1 + 1) + N1; 22 printf("20248329%04d\n", random_no); 23 } 24 else { 25 random_no = rand() % N3 + 1; 26 printf("20248395%04d\n", random_no); 27 } 28 29 cnt++; 30 } 31 32 return 0; 33 }
回答问题
问题1. line 21使抽取到的在202483290397-202483290476的范围内随机。
问题2. line 24使抽取到的在202483950001-202483950021的范围内随机。
问题3. 该程序可以在202483290397-202483290476和202483950001-202483950021的范围内随机抽取5个学号。
实验任务二
task2.c
1 #include <stdio.h> 2 #include <math.h> 3 4 int main() { 5 double a, b, c; 6 double delta, p1, p2; 7 8 while(scanf("%lf%lf%lf", &a, &b, &c) != EOF) { 9 if(a == 0) { 10 printf("a = 0, invalid input\n"); 11 continue; 12 } 13 14 delta = b*b - 4*a*c; 15 p1 = -b/2/a; 16 p2 = sqrt(fabs(delta))/2/a; 17 18 if(delta == 0) 19 printf("x1 = x2 = %.2g\n", p1); 20 else if(delta > 0) 21 printf("x1 = %.2g, x2 = %.2g\n", p1+p2, p1-p2); 22 else { 23 printf("x1 = %.2g + %.2gi, ", p1, p2); 24 printf("x2 = %.2g - %.2gi\n", p1, p2); 25 } 26 } 27 28 return 0; 29
实验任务3
task3.c
1 #include<stdio.h> 2 int main(){ 3 char color; 4 while (scanf("%c",&color) != EOF){ 5 getchar(); 6 if (color =='r') printf("stop!\n"); 7 else if (color == 'g') printf("go go go\n"); 8 else if (color == 'y') printf("wait a minute\n"); 9 else printf("something must be wrong\n"); 10 11 } 12 return 0; 13 }
实验任务4
1 #include<stdio.h> 2 int main(){ 3 double expense,max=0,min=20000,total=0; 4 printf("输入今日开销,直到输入-1终止:\n"); 5 while (1) { 6 scanf("%lf",&expense); 7 if (expense==-1){ 8 break; 9 } 10 total=total+expense; 11 if (expense >max){ 12 max=expense; 13 } 14 if (expense <min){ 15 min=expense; 16 } 17 } 18 printf("今日累计消费总额:%.1lf\n",total); 19 printf("今日最高一笔开销:%.1lf\n",max); 20 printf("今日最低一笔开销:%.1lf\n",min); 21 return 0; 22 }
实验任务5
task5.c
1 #include<stdio.h> 2 int main(){ 3 int a,b,c; 4 while (scanf("%d%d%d",&a,&b,&c) != EOF){ 5 if(a+b<=c || a+c<=b ||b+c<=a){ 6 printf("不能构成三角形\n"); 7 } 8 else{ 9 if (a==b && b==c) printf("等边三角形\n"); 10 else if ((a*a +b*b==c*c||b*b+c*c==a*a||a*a+c*c==b*b)&&(a==b ||b==c||a==c)) printf("等腰直角三角形\n"); 11 else if (a*a +b*b==c*c||b*b+c*c==a*a||a*a+c*c==b*b) printf("直角三角形\n"); 12 else if (a==b ||b==c||a==c) printf("等腰三角形\n"); 13 else printf("普通三角形\n"); 14 } 15 } 16 return 0; 17 }
实验任务6
task6.c
1 #include<stdio.h> 2 #include<stdlib.h> 3 #include<time.h> 4 int main(){ 5 int i=3,n,n1,rdm; 6 srand(time(NULL)); 7 rdm=1+rand()%30; 8 printf("猜猜2024年11月哪一天会是你的lucky day\n开始喽,你有三次机会,猜吧(1~30):"); 9 while(scanf("%d",&n) != EOF){ 10 if (n==rdm) { 11 printf("哇,猜中了:)\n"); 12 return 0; 13 } 14 else if (n<rdm) { 15 printf("你猜的日期早了,你的lucky day还没到呢\n"); 16 printf("再猜(1~30):"); 17 } 18 else{ 19 printf("你猜的日期晚了,你的lucky day在前面哦\n"); 20 printf("再猜(1~30):"); 21 } 22 i--; 23 if (i<=0) { 24 break; 25 } 26 } 27 printf("次数用光啦。偷偷告诉你,11月你的lucky day是%d号",rdm); 28 return 0; 29 }
标签:random,int,编程,expense,%.,循环,printf,include,分支 From: https://www.cnblogs.com/wyhzmd/p/18462156