以图示为例:
Node root = new Node("A",
new Node("B",
new Node("C"), new Node("D")),
new Node("E",
new Node("F"), new Node("G",
null, new Node("H"))));
DFS:
public static void DFS(Node root)
{
Stack<Node> stack = new Stack<Node>();
stack.Push(root);
while (stack.Count > 0)
{
Node node = stack.Pop();
Console.Write(node.Value + " ");
if (node.Right != null)
{
stack.Push(node.Right);
}
if (node.Left != null)
{
stack.Push(node.Left);
}
}
}
public static void DFS_Recursion(Node root)
{
if (root == null)
return;
Console.Write(root.Value + " ");
DFS_Recursion(root.Left);
DFS_Recursion(root.Right);
}
BFS:
public static void BFS(Node root)
{
Queue<Node> queue = new Queue<Node>();
queue.Enqueue(root);
while (queue.Count > 0)
{
Node node = queue.Dequeue();
Console.Write(node.Value + " ");
if (node.Left != null)
{
queue.Enqueue(node.Left);
}
if (node.Right != null)
{
queue.Enqueue(node.Right);
}
}
}
Main函数:
Console.WriteLine("BFS:");
BFS(root);
Console.WriteLine("\nDFS:");
DFS(root);
Console.WriteLine("\nDFS_Recursion:");
DFS_Recursion(root);
输出:
BFS:
A B E C D F G H
DFS:
A B C D E F G H
DFS_Recursion:
A B C D E F G H
标签:node,Node,C#,DFS,BFS,new,root
From: https://www.cnblogs.com/sanzhixiaozhu/p/18284365