4. 实验任务4
1 #include<stdio.h>
2 #define N 10
3
4 typedef struct {
5 char isbn[20];
6 char name[80];
7 char author[80];
8 double sales_price;
9 int sales_count;
10 }Book;
11
12 void output(Book x[],int);
13 void sort(Book x[],int n);
14 double sales_amount(Book x[],int);
15
16 int main()
17 {
18 Book x[N]={{"978-7-229-14156-1","源泉","安·兰德",84,59},
19 {"978-7-5133-5261-1", "李白来到旧金山", "谭夏阳",48,16},
20 {"978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6,27},
21 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
22 {"978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49, 42},
23 {"978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39},
24 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5,55},
25 {"978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31},
26 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118,42},
27 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5,44}};
28
29 printf("图书馆销量排名：\n");
30 sort(x,N);
31 output(x,N);
32
33 printf("\n图书馆销售总额：%.2lf\n",sales_amount(x,N));
34
35 return 0;
36 }
37 void output(Book x[],int n)
38 {
39 int i;
40
41 printf("ISBN号\t\t\t书名\t\t\t\t作者\t\t\t售价\t\t销售册数\n");
42
43 for(i=0;i<n;++i)
44 printf("%-24s%-32s%-20s\t%-13.2lf\t%4d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
45 }
46 void sort(Book x[],int n)
47 {
48 int i,j,k;
49 Book min;
50
51 for(i=0;i<n-1;++i)
52 {
53 for(j=1,min=x[0],k=0;j<n-i;++j)
54 if(x[j].sales_count<min.sales_count)
55 {
56 min=x[j];
57 k=j;
58 }
59 x[k]=x[j-1];
60 x[j-1]=min;
61 }
62 }
63 double sales_amount(Book x[],int n)
64 {
65 int i;
66 double s=0;
67
68 for(i=0;i<n;++i)
69 s+=x[i].sales_count*x[i].sales_price;
70
71 return s;
72 }
5. 实验任务5
1 #include<stdio.h>
2 typedef struct
3 {
4 int year;
5 int month;
6 int day;
7 }Date;
8
9 void input(Date *pd);
10 int day_of_year(Date d);
11 int compare_dates(Date d1,Date d2);
12
13 void test1();
14 void test2();
15
16 int main()
17 {
18 printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
19 test1();
20
21 printf("\n测试2: 两个人年龄大小关系\n");
22 test2();
23
24 return 0;
25 }
26 void test1()
27 {
28 Date d;
29 int i;
30
31 printf("输入日期:(以形如2024-06-01这样的形式输入)\n");
32 for(i = 0; i < 3; ++i) {
33 input(&d);
34 printf("%04d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
35 }
36
37 }
38 void test2()
39 {
40 Date Alice_birth, Bob_birth;
41 int i;
42 int ans;
43
44 printf("输入Alice和Bob出生日期:(以形如2005-08-11这样的形式输入)\n");
45 for(i = 0; i < 3; ++i)
46 {
47
48 input(&Alice_birth);
49 input(&Bob_birth);
50 ans=compare_dates(Alice_birth,Bob_birth);
51
52 if(ans==0)
53 printf("Alice和Bob一样大\n\n");
54 else if(ans == -1)
55 printf("Alice比Bob大\n\n");
56 else
57 printf("Alice比Bob小\n\n");
58 }
59
60 }
61 void input(Date *pd)
62 {
63 scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
64 }
65 int day_of_year(Date d)
66 {
67 int i,s=0;
68
69 for(i=1;i<d.month;++i)
70 if(i==1||i==3||i==5||i==7||i==8||i==10||i==12)
71 s+=31;
72 else if(i==2)
73 if(d.year%4==0&&d.year%100!=0 ||d.year%400==0)
74 s+=29;
75 else
76 s+=28;
77 else
78 s+=30;
79
80 s+=d.day;
81
82 return s;
83 }
84 int compare_dates(Date d1,Date d2)
85 {
86 if(d1.year>d2.year)
87 return 1;
88 else if(d1.year<d2.year)
89 return -1;
90 else if(d1.month>d2.month)
91 return 1;
92 else if(d1.month<d2.month)
93 return -1;
94 else if(d1.day>d2.day)
95 return 1;
96 else if(d1.day<d2.day)
97 return -1;
98 else
99 return 0;
100 }
6. 实验任务6
1 #include<stdio.h>
2 #include<string.h>
3 #define N 20
4
5 enum Role{admin,student,teacher};
6
7 typedef struct
8 {
9 char username[N];
10 char password[N];
11 enum Role type;
12
13 }Account;
14
15 void output(Account x[],int n);
16
17 int main()
18 {
19 Account x[]={{"A1001", "123456", student},
20 {"A1002", "123abcdef", student},
21 {"A1009", "xyz12121", student},
22 {"X1009", "9213071x", admin},
23 {"C11553", "129dfg32k", teacher},
24 {"X3005","921kfmg917",student}};
25 int n;
26 n=sizeof(x)/sizeof(Account);
27 output(x,n);
28
29 return 0;
30 }
31 void output(Account x[],int n)
32 {
33 int i,k,m;
34
35 for(i=0;i<n;++i)
36 {
37 printf("%-10s\t",x[i].username);
38
39 for(k=0;x[i].password[k]!=0;k++)
40 printf("*");
41
42 printf(" \t");
43
44 m=x[i].type;
45
46 if(m==0)
47 printf("admin");
48 else if(m==1)
49 printf("student");
50 else
51 printf("teacher");
52
53 printf("\n");
54 }
55 }
7. 实验任务7
1 #include<stdio.h>
2 #include<string.h>
3 typedef struct
4 {
5 char name[20];
6 char phone[12];
7 int vip;
8 }Contact;
9
10 void set_vip_contact(Contact x[],int n,char name[]);
11 void output(Contact x[],int n);
12 void display(Contact x[],int n);
13
14 #define N 10
15
16 int main()
17 {
18 Contact list[N]={{"刘一", "15510846604", 0},
19 {"陈二", "18038747351", 0},
20 {"张三", "18853253914", 0},
21 {"李四", "13230584477", 0},
22 {"王五", "15547571923", 0},
23 {"赵六", "18856659351", 0},
24 {"周七", "17705843215", 0},
25 {"孙八", "15552933732", 0},
26 {"吴九", "18077702405", 0},
27 {"郑十", "18820725036", 0}};
28 int vip_cnt,i;
29 char name[20];
30
31 printf("显示原始通讯录信息：\n");
32 output(list,N);
33
34 printf("\n输入要设置的紧急联系人个数：");
35 scanf("%d",&vip_cnt);
36 printf("输入%d个紧急联系人姓名：\n",vip_cnt);
37 for(i=0;i<vip_cnt;++i)
38 {
39 scanf("%s",name);
40 set_vip_contact(list,N,name);
41 }
42
43 printf("\n显示通讯录列表：(按姓名字典升序排列，紧急联系人最先显示)\n");
44 display(list,N);
45 output(list,N);
46
47 return 0;
48 }
49 void set_vip_contact(Contact x[],int n,char name[])
50 {
51 int i;
52
53 for(i=0;i<n;++i)
54 if(strcmp(name,x[i].name)==0)
55 {
56 x[i].vip=1;
57 break;
58 }
59 }
60 void display(Contact x[],int n)
61 {
62 int i,j,k=0;
63 Contact t;
64
65 for(i=0;i<n;++i)
66 if(x[i].vip)
67 {
68 t=x[i];
69 x[i]=x[k];
70 x[k++]=t;
71 }
72
73 for(i=0;i<k-1;++i)
74 for(j=0;j<k-i-1;++j)
75 if(strcmp(x[j].name,x[j+1].name)>0)
76 {
77 t=x[j];
78 x[j]=x[j+1];
79 x[j+1]=t;
80 }
81 for(i=k;i<n;++i)
82 for(j=k;j<n-1;++j)
83 if(strcmp(x[j].name,x[j+1].name)>0)
84 {
85 t=x[j];
86 x[j]=x[j+1];
87 x[j+1]=t;
88 }
89 }
90 void output(Contact x[],int n)
91 {
92 int i;
93
94 for(i=0;i<n;++i)
95 {
96 printf("%-10s%-15s",x[i].name,x[i].phone);
97 if(x[i].vip)
98 printf("%5s","*");
99 printf("\n");
100 }
101 }
标签：int,void,编程,C语言,枚举,printf,Date,output,978 From： https://www.cnblogs.com/zbb07/p/18240621