C++PrimerPlus第十一章类的使用 :练习7 复数类的实现和重载运算符对复数做运算----本章完结

7. 复数有两个部分组成:实数部分和虚数部分。复数的一种书写方式是:(3.0，4.0)，
   其中，3.0是实数部分，4.0是虚数部分。假设a=(A,Bi)，c=(C,Di)，则下面是一些复数运算。

加法:a+c=(A+C,(B+D)i)。

减法:a-c=(A-C,(B-D)i)。

乘法:ac=(AC-BD,(AD+B*C)i)。

乘法::xc=(xC,x*Di)，其中x为实数。

共轭:~a=(A,-Bi)。

请定义一个复数类，以便下面的程序可以使用它来获得正确的结果。

#ifndef PE11_7_H_
#define PE11_7_H_

#include<iostream>

class Complex
{
private:
	struct Complex_t
	{
		double a;
		double bi;
	};
	double a;
	double bi;
	Complex_t comlex;
	void SetComplex(void);
	void SetABi(void);
public:
	Complex(double a = 0, double bi = 0);

	friend std::ostream& operator<<(std::ostream& os, const Complex& a);
	friend std::istream& operator>>(std::istream& is, Complex& a);
	Complex operator+(Complex& a);
	Complex operator-(Complex& a);
	Complex operator*(Complex& a);
	friend Complex operator~(Complex& a);
	friend Complex operator*(double n,Complex& a);
	
};
#endif // !1

#include"pe11_7.h"
#include<iostream>
using namespace std;
Complex::Complex(double a, double bi)
{
	this->a = a;
	this->bi = bi;
	SetComplex();
}
void Complex::SetComplex(void)
{
	this->comlex.a = this->a;
	this->comlex.bi = this->bi;
}
void Complex::SetABi()
{
	this->a = this->comlex.a;
	this->bi = this->comlex.bi;
}

ostream& operator<<(ostream& os, const Complex& a)
 {
	 os << "(" << a.a << "," << a.bi << "i)";
	 return os;
 }

istream& operator>>(istream& is, Complex& a)
 {
	 cout << "real: ";
	 is >> a.a;
	 if (!is)
	 {
		 is.ignore(numeric_limits<streamsize>::max(), '\n');
		 return (is);
	 }
	 cout << "imaginary: ";
	 is >> a.bi;
	 if (!is)
	 {
		 is.ignore(numeric_limits<streamsize>::max(), '\n');
	 }
	 return (is);
}
Complex Complex::operator+(Complex& a)
{
	Complex temp;
	temp.a = this->a + a.a;
	temp.bi = this->bi + a.bi;
	return temp;
}
Complex Complex::operator-(Complex& a)
{
	Complex temp;
	temp.a = this->a - a.a;
	temp.bi = this->bi - a.bi;
	return temp;
}
Complex Complex::operator*(Complex& a)
{
	Complex temp;
	temp.a = this->a * a.a - this->bi * a.bi;
	temp.bi = this->a * a.bi + this->bi * a.a;
	return temp;
}
Complex operator*(double n, Complex& a)
{
	Complex temp;
	temp.a = n*a.a;
	temp.bi = n*a.bi;
	return temp;
}

 Complex operator~(Complex& a)
{
	 Complex temp;
	 temp.a = a.a;
	 temp.bi = -a.bi;
	
	 return temp;
}

#pragma region 练习7.cpp
/*

*/
#if 1
#include <iostream>
#include"pe11_7.h"
int main()
{
	using namespace std;
	Complex a(3.0, 4.0);  //to avid confusion with complex.h
	Complex c ;

	cout << "Enter a complex number(q to quit):\n";
	while (cin>>c)
	{
		cout << "C is " << c << "\n";
		cout << "complex conjugate is " << ~c << "\n";
		cout << "a is " << a << "\n";
		cout << "a + c is " << a + c << "\n";
		cout << "a - c is " << a - c << "\n";
		cout << "a*c is " << a * c << "\n";
		cout << "2*c is " << 2 * c << '\n';
		cout << "Enter a complex number(q to quit):\n";
	}
	cout << "Done!\n";
	return 0;
}
#endif 
#pragma endregion

测试符合题目要求