def list_submodules(self,package_path):
"""递归地列出给定包路径下的所有子模块"""
all_submodules = []
# 遍历包路径下的所有文件/目录
for importer, modname, ispkg in pkgutil.iter_modules([package_path]):
full_modname = modname
module_path = os.path.join(package_path, modname)
# 如果是子包，则递归调用list_submodules
if ispkg:
# 构建子包的完整路径
subpackage_path = os.path.join(module_path, '__init__.py')
# 递归查找子包下的子模块
submodules = self.list_submodules(subpackage_path)
# 添加子模块名称到结果列表，同时保留子包的路径
all_submodules.extend([full_modname + '.' + submodule for submodule in submodules])
else:
# 添加非包模块的完整名称
all_submodules.append(full_modname)
return all_submodules
标签：modname,full,submodules,python,package,模块,某个,path From： https://www.cnblogs.com/shunguo/p/18064743