反转一个只有3位数的整数。输入 789,反转后输出 987. 代码如下: Reverse.py
class Solution:
#参数 Number:一个3位数字
#返回值:反转后的数字
def reverseInteger(self, number):
h = int(number/100)
t = int(number % 100/10)
z = int(number % 10)
return (100 * z + 10 * t + h)
if __name__ == '__main__':
solution = Solution()
num = 789
ans = solution.reverseInteger(num)
print("输入:", num)
print("输出:", ans)
输出:
D:\Code\python\pythonclass01\.venv\Scripts\python.exe D:\Code\python\pythonclass01\Reversedigit.py
输入: 789
输出: 987
进程已结束,退出代码为 0
标签:__,Python,反转,编程,number,789,int,num,python
From: https://blog.51cto.com/sunproblem/9127235