一，实验目的
二，实验准备
三，实验内容
1，实验任务1
task1.c
1 #include<stdio.h>
2 #include<stdlib.h>
3 #include<time.h>
4 #include<Windows.h>
5 #define N 80
6
7 void print_text(int line, int col,char text[]);//函数声明
8 void print_spaces(int n);//函数声明
9 void print_blank_lines(int n);//函数声明
10
11 int main()
12 {
13 int line,col,i;
14 char text[N] = "hi,November";
15
16 srand(time(0));//以当前系统时间作为随机种子
17
18 for(i=1;i<=1;++i)
19 {
20 line = rand()%25;
21 col = rand()%80;
22 print_text(line,col,text);
23 Sleep(1000);//暂停1000ms
24 }
25 return 0;
26 }
27
28 //打印n个空格
29 void print_spaces(int n)
30 {
31 int i;
32
33 for(i=1;i<=n;++i)
34 printf(" ");
35 }
36
37 //打印n个空格
38 void print_blank_lines(int n)
39 {
40 int i;
41
42 for(i=1;i<=n;++i)
43 printf("\n");
44 }
45
46 //在第line行第col列打印一段文本
47 void print_text(int line,int col,char text[])
48 {
49 print_blank_lines(line-1);
50 print_spaces(col-1);
51 printf("%s",text);
52 }
在随机位置生成文本"hi,November"。
2，实验任务2
task2_1.c
1 //利用局部static变量的特性，计算阶乘
2
3 #include<stdio.h>
4 long long fac(int n);//函数声明
5
6 int main()
7 {
8 int i,n;
9
10 printf("Enter n:");
11 scanf("%d",&n);
12 for(i=1;i<=n;++i)
13 printf("%d!=%lld\n",i,fac(i));
14
15 return 0;
16 }
17
18 //函数定义
19 long long fac(int n)
20 {
21 static long long p = 1;
22
23 p = p*n;
24
25 return p;
26 }
1 //利用局部static变量的特性，计算阶乘
2
3 #include<stdio.h>
4 long long fac(int n);//函数声明
5
6 int main()
7 {
8 int i,n;
9
10 printf("Enter n:");
11 scanf("%d",&n);
12 for(i=1;i<=n;++i)
13 printf("%d!=%lld\n",i,fac(i));
14
15 return 0;
16 }
17
18 //函数定义
19 long long fac(int n)
20 {
21 static long long p = 1;
22 printf("p=%lld\n",p);
23 p = p*n;
24
25 return p;
26 }
task2_2.c
p1=8,p2=17.
1 //练习:局部static变量特性
2
3 #include<stdio.h>
4 int func(int,int); //函数声明
5
6 int main()
7 {
8 int k=4,m=1,p1,p2;
9
10 p1=func(k,m);
11 p2=func(k,m);
12 printf("%d,%d\n",p1,p2);
13
14 return 0;
15 }
16
17 //函数定义
18 int func(int a,int b)
19 {
20 static int m=0,i=2;
21
22 i+=m+1;
23 m=i+a+b;
24 return m;
25 }
static修饰的变量会发生变化。
3，实验任务3
task3.c
1 #include<stdio.h>
2 long long func(int n);//函数声明
3
4 int main()
5 {
6 int n;
7 long long f;
8
9 while(scanf("%d",&n)!=EOF)
10 {
11 f=func(n);//函数调用
12 printf("n=%d,f=%lld\n",n,f);
13 }
14
15 return 0;
16 }
17 long long func(int n)
18 {
19 long long int ans;
20 if(n==0)
21 ans=0;
22 else
23 ans=2*(func(n-1)+1)-1;
24 return ans;
25 }
4，实验任务4
task4.1.c
1 #include<stdio.h>
2 int func(int n,int m);
3
4 int main()
5 {
6 int n, m;
7
8 while(scanf("%d%d", &n, &m) != EOF)
9 printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));
10
11 return 0;
12 }
13
14 int func(int n,int m)
15 {
16 int i,s;
17 int a=1,b=1,c=1;
18 for(i=1;i<=n;++i)
19 a*=i;
20 for(i=1;i<=m;++i)
21 b*=i;
22 for(i=1;i<=n-m;++i)
23 c*=i;
24 s=a/(b*c);
25 return s
26 }
task4.2.c
1 #include<stdio.h>
2 int func(int n,int m);
3
4 int main()
5 {
6 int n,m;
7
8 while(scanf("%d%d", &n, &m) != EOF)
9 printf("n = %d, m = %d, ans = %d\n", n, m, func(n,m));
10
11 return 0;
12 }
13
14 int func(int n,int m)
15 {
16 int ans;
17 if(n<m)
18 return 0;
19 if(n==0)
20 return 0;
21 if(m==0)
22 return 1;
23 else if(m==1)
24 return n;
25 else
26 ans=func(n-1,m)+func(n-1,m-1);
27 return ans;
28 }
5，实验任务5
task5.c
1 //Hanoi塔求解
2 #include<stdio.h>
3 #include<stdlib.h>
4 void hanoi( unsigned int n,char from,char temp,char to);//from=A,temp=B,to=C
5 void moveplate(unsigned int n,char from,char to);//n,表示第n个盘子
6 static int m=0;
7
8 int main()
9 {
10 unsigned int n;
11 while(scanf("%u",&n) !=EOF)
12 {
13 hanoi(n,'A','B','C');
14 printf("\n");
15 printf("一共移动了%d次",m);
16 m=0;
17 }
18 system("pause");
19 return 0;
20 }
21 void hanoi( unsigned int n,char from,char temp,char to)
22 {
23 static int m=1;
24 if(n == 1)
25 {
26 moveplate(n,from,to);//moveplate
27 m+=1;
28 }
29 else
30 {
31 hanoi(n-1,from,to,temp);
32 moveplate(n,from,to);
33 hanoi(n-1,temp,from,to);
34 m+=1;
35 }
36 }
37 void moveplate(unsigned int n,char from,char to)
38 {
39 printf("%u:%c-->%c\n",n,from,to);
40 ++m;
41 }
6，实验任务6
task6.c
1 int main()
2 {
3 long s, t;
4 printf("Enter a number: ");
5 while (scanf("%ld", &s) != EOF)
6 {
7 t = func(s); // 函数调用
8 printf("new number is: %ld\n\n", t);
9 printf("Enter a number: ");
10 }
11 return 0;
12 }
13
14 long func(long s)
15 {
16 long a,n=0;
17 float i=0;
18 while(s>0)
19 {
20 a=s%10;
21 s=s/10;
22 if(a%2!=0)
23 {
24 n=a*pow(10,i)+n;
25 ++i;
26 }
27 }
28 return n;
29 }
7，实验任务7
task7.c
1 #include<stdio.h>
2
3 int main()
4 {
5 int A,B;
6 int i=0,j=0;
7 int s=1,n=0,m=0;
8 while(s!=0)
9 {
10 int a[10],b[10];
11 A=s*s;
12 B=s*s*s;
13 while(A!=0)
14 {
15 a[i]=A%10;
16 A=A/10;
17 ++i;
18 ++n;
19 }
20 while(B!=0)
21 {
22 b[j]=B%10;
23 B=B/10;
24 ++j;
25 ++m;
26 }
27 if(n+m==10)
28 {
29 int count=0;
30 for(i=0;i<n;++i)
31 {
32 for(j=0;j<m;++j)
33 {
34 if(a[i]==b[j])
35 count++;
36 }
37 }
38 if(count==0)
39 {
40 printf("%d",s);
41 return 0;
42 }
43 else
44 {
45 ++s;
46 continue;
47 }
48 }
49 else
50 {
51 ++s;
52 continue;
53 }
54 }
55 return 0;
56 }
四，实验结论
见上
五，实验总结
标签：10,函数,int,编程,long,C语言,func,printf,include From： https://www.cnblogs.com/lze0389/p/17798087.html