代码逆向
在这里需要注意的几个点：
- c#语言赋值号（=）右边的值同样会跟着左边的值改变，如array6=array2，array6+=2；这个时候array2也会变
- 如array7[num5] += text2[k] % '\u0005';，逆向则为array7【num5】-=ord（text【k】）%5，即chr-->ord
- 空格的ASCII为32
则逆向代码为
v6 = 35
j = 0
v10 =[68,75,66,72,99,19,19,78,83,74,91,86,35,39,77,85,44,89,47,92,49,88,48,91,88,102,105,51,76,115,-124,125,79,122,-103]
a2 = "NEWSTAR"
for j in range(7):
v10[j + 28] -= (ord(a2[j])//5) + 10
v10[j + 21] -= j ^ 2 v10[j + 14] -= 2 * j
v10[j + 7] -= ord(a2[j]) % 5
v10[j] -= j ^ -(ord(a2[j]) % 4)
for i in range(v6):
v10[i] -= i
v10[i] += 32
print(chr(v10[i]%256), end='')
标签：逆向,num5,v10,C++,88,a2,ord From： https://www.cnblogs.com/lhqrusht0p/p/17781820.html