简单说明:
1.冒泡排序:双层循环,交替结果
2.选择排序:while nums,假设第一个值为做小,通过for循环找到最小值以此来替换,再将nums中该值去掉继续上述步骤
3.快速排序:定义一个初值,把整个数据列表分为两部分,再递归
代码实现:
# 冒泡排序 def action1(n): for i in range(len(n)): for j in range(len(n)): if n[i] < n [j]: tmp = n[i] n[i] = n[j] n[j] = tmp print(n) # 选择排序 def choice_order(n): sm = n[0] si = 0 for i in range(len(n)): if n[i] < sm: sm = n[i] return sm def action2(n): rs = [] while n: res = choice_order(n) rs.append(res) n.remove(res) print(rs) # 快速排序 def action3(n): if len(n) < 2: return n num = n[0] less = [i for i in n if i < num] more = [i for i in n if i > num] return action3(less) + [num] + action3(more) if __name__ == '__main__': nums = [1, 6, 3, 2, 7] # 冒泡排序 action1(nums) # 选择排序 action2(nums) # 快速排序 res = action3(nums) print(res)
标签:__,nums,Python,res,action3,num,冒泡,排序 From: https://www.cnblogs.com/lytcreate/p/17755464.html