在线验证算法
算法实现
1. 快排
思路
树的前序遍历。
每次选取一个数作基准值,将小于基准值的数放在左边,大于基准值的数放在右边。遍历左子树及右子树,直到只有1个数为止。
实现
class QuickSort {
public static void sort(int[] nums) {
shuffle(nums);
sort(nums, 0, nums.length - 1);
}
public static void sort(int[] nums, int left, int right) {
if (left >= right) return;
int pivot = partition(nums, left, right);
sort(nums, left, pivot - 1);
sort(nums, pivot + 1, right);
}
public static int partition(int[] nums, int lo, int hi) {
int i = lo;
for (int j = lo; j < hi; j++) {
if (nums[j] < nums[hi]) {
swap(nums, i++, j);
}
}
swap(nums, i, hi);
return i;
}
public static void shuffle(int[] nums) {
Random random = new Random();
int n = nums.length;
for (int i = 0; i < n; i++)
swap(nums, i, random.nextInt(n - i) + i);
}
public static void swap(int[] nums, int i, int j) {
int temp = nums[i];
nums[i] = nums[j];
nums[j] = temp;
}
}
2. 归并
思路
树的后序遍历。
将左子树及右子树分别排序后合并。
合并时避免多次创建临时数组,可以使用同一个临时数组。
实现
class MergeSort {
private static int[] temp;
public static void sort(int[] nums) {
temp = new int[nums.length];
sort(nums, 0, nums.length - 1);
}
public static void sort(int[] nums, int left, int right) {
if (left >= right) return;
int mid = left + (right - left) / 2;
sort(nums, left, mid);
sort(nums, mid + 1, right);
merge(nums, left, mid, right);
}
public static void merge(int[] nums, int left, int mid, int right) {
for (int i = left; i <= right; i++)
temp[i] = nums[i];
int i = left, j = mid + 1, k = left;
while (i <= mid && j <= right) {
if (temp[i] < temp[j]) {
nums[k++] = temp[i++];
} else {
nums[k++] = temp[j++];
}
}
while (i <= mid)
nums[k++] = temp[i++];
while (j <= right)
nums[k++] = temp[j++];
}
public static void swap(int[] nums, int i, int j) {
int temp = nums[i];
nums[i] = nums[j];
nums[j] = temp;
}
}
标签:sort,right,nums,int,算法,static,排序,left
From: https://www.cnblogs.com/kiper/p/17741324.html