python3 生成二年级下计算练习,有口算,有竖式。
import random import osfrom docx.shared import Pt from docx import Document def create_page(document): #口算 document.add_paragraph('一、口算') operators='+-×÷' columnsNumber = 3 rowsNumbers = 8 table = document.add_table(rows=rowsNumbers, cols=columnsNumber) for row in range(rowsNumbers): for col in range(columnsNumber): operator = random.choice(operators) first = random.randint(11, 100) second = random.randint(11, 100) if operator == '×' or operator == '÷': first = random.randint(2, 9) second = random.randint(2, 9) if operator == '÷': first=first*second if operator == '-' or operator == '+': if first < second: first, second = second, first if second < 30: first*=10 second*=10 if second < 20: first*=10 second*=10 if operator == '+': first=first-second r = str(first) + ' ' + operator +' '+ str(second) + '=' cell = table.cell(row, col) cell.text = r #竖式 document.add_paragraph('') document.add_paragraph('二、竖式') operators='+-÷' columnsNumber = 5 rowsNumbers = 7 table = document.add_table(rows=rowsNumbers, cols=columnsNumber) for row in range(int(rowsNumbers/4)+1): for col in range(int(columnsNumber/2)+1): operator = random.choice(operators) first = random.randint(100, 1000) second = random.randint(100, 1000) if operator == '÷': first = random.randint(2, 9) second = random.randint(2, 9) residue = random.randint(1, second-1) first=first*second+residue if operator == '-' or operator == '+': if first < second: first, second = second, first if operator == '+': first=first-second r = str(first) + ' ' + operator +' '+ str(second) + '=' cell = table.cell(row*4, col*2) cell.text = r def create_docx(): document = Document() document.styles['Normal'].font.name = '微软雅黑' document.styles['Normal'].font.size = Pt(12) pageSize=10 # 页数 for i in range(0,pageSize): if i!=0: document.add_page_break() create_page(document) document.save('二年级下计算练习.docx') os.startfile("二年级下计算练习.docx") if __name__ == '__main__': create_docx()
标签:docx,random,randint,python,练习,second,operator,document,first From: https://www.cnblogs.com/SamFang/p/17495417.html