你能实现这样一个函数吗:
MyType type;
HisType htype;
serialize_3(11, type, htype);
serialize_4(type, htype ,type, htype);
serialize_4(11, type , htype, htype);
参数类型自由,个数自由,怎么做呢?往下看:
[xiaochu.yh@OB macro]$ cat auto_type.cpp
/*
* (C) 1999-2013 Alibaba Inc.
*
* This program is free software; you can redistribute it and/or modify
* it under the terms of the GNU General Public License version 2 as
* published by the Free Software Foundation.
*
*
* Version: auto_type.cpp, 09/04/2013 08:02:17 PM Yu Huang Exp $
*
* Author:
* Huang Yu <[email protected]>
* Description:
* auto type match
*
*/
#include <stdio.h>
void serialize()
{
return;
}
class HisType
{
public:
HisType(const char *i) : value_(i) { }
~HisType() { }
void serialize() const
{
printf("HisType: s(%s)\n", value_);
}
private:
const char *value_;
};
class MyType
{
public:
MyType(int i) : value_(i) { }
~MyType() { }
void serialize() const
{
printf("MyType: f(%d)\n", value_);
}
private:
int value_;
};
void serialize(const int arg0)
{
printf("int: %d\n", arg0);
}
void serialize(const float arg0)
{
printf("float: %f\n", arg0);
}
template<typename Arg0>
void serialize(const Arg0 &arg0)
{
arg0.serialize();
}
template<typename Arg0>
void serialize_1(const Arg0 &arg0)
{
serialize(arg0);
}
#define JOIN(x,y) JOIN2(x,y)
#define JOIN2(x,y) x##y
#define DECVAL_1 0
#define DECVAL_2 1
#define DECVAL_3 2
#define DECVAL_4 3
#define DEC_VAL(n) DECVAL_##n
// recursively expanding macro
#define ARG_TN0
#define ARG_TN1 typename Arg0
#define ARG_TN2 ARG_TN1, typename Arg1
#define ARG_TN3 ARG_TN2, typename Arg2
#define ARG_TN4 ARG_TN3, typename Arg3
#define ARG_PN0
#define ARG_PN1 const Arg0 & arg0
#define ARG_PN2 ARG_PN1, const Arg1 & arg1
#define ARG_PN3 ARG_PN2, const Arg2 & arg2
#define ARG_PN4 ARG_PN3, const Arg3 & arg3
#define ARG_AN0
#define ARG_AN1 arg0
#define ARG_AN2 ARG_AN1, arg1
#define ARG_AN3 ARG_AN2, arg2
#define ARG_AN4 ARG_AN3, arg3
#define ARG_CN0
#define ARG_CN1 arg0
#define ARG_CN2 arg1
#define ARG_CN3 arg2
#define ARG_CN4 arg3
#define SERIALIZE_DECLARE(NUM_ARG) \
template<JOIN(ARG_TN, NUM_ARG)> \
void JOIN(serialize_, NUM_ARG)(JOIN(ARG_PN, NUM_ARG))
SERIALIZE_DECLARE(2);
SERIALIZE_DECLARE(3);
SERIALIZE_DECLARE(4);
#define SERIALIZE_DEFINE(NUM_ARG) \
template<JOIN(ARG_TN, NUM_ARG)> \
void JOIN(serialize_, NUM_ARG)(JOIN(ARG_PN, NUM_ARG)) \
{ \
JOIN(serialize_, DEC_VAL(NUM_ARG))(JOIN(ARG_AN, DEC_VAL(NUM_ARG))); \
serialize(JOIN(ARG_CN, NUM_ARG)); \
}
SERIALIZE_DEFINE(2);
SERIALIZE_DEFINE(3);
SERIALIZE_DEFINE(4);
int main()
{
MyType type(4234);
HisType htype("home");
//先来个见面礼, 1是int类型,10.2f是float类型,type是自定义类型
serialize_4(1,10.2f,3, type);
printf("==============\n");
serialize_3(type,11, htype); // <== 注意下面的参数个数,以及参数顺序,完全自由!
printf("==============\n");
serialize_3(11 ,type, htype);
printf("==============\n");
serialize_3(htype ,type, htype);
printf("==============\n");
return 0;
}
编译运行结果:
[xiaochu.yh@OB macro]$ g++ auto_type.cpp
[xiaochu.yh@OB]$ ./a.out
int: 1
float: 10.200000
int: 3
MyType: f(4234)
==============
MyType: f(4234)
int: 11
HisType: s(home)
==============
int: 11
MyType: f(4234)
HisType: s(home)
==============
HisType: s(home)
MyType: f(4234)
HisType: s(home)
==============
该技术是从曲山同学的代码中学习来的,曲山对宏的运用真是炉火纯青!这里最神奇的就是下面一段代码,至今不明:
#define JOIN(x,y) JOIN2(x,y)
#define JOIN2(x,y) x##y
JOIN和JOIN2不是等价的吗?不过还真不是。如果只写JOIN2,在宏展开阶段会有比较诡异的事情发生。不信你试试。但是为什么呢?我也不知道。@曲山,求助啊~~
更全面的代码见OceanBase源码oceanbase/src/common/ob_rpc_stub.h和oceanbase/src/common/ob_rpc_macros.h
=============================================
UPDATE:
这篇帖子发到了内网,得到了@探晴同学指点,加上@元启 同学的解释,基本弄明白了JOIN的机制。
原因的确很简单。
#define MY_VALUE 2
#define JOIN(A,B) A##B
JOIN(hello, world)的输出结果就是 helloworld,
JOIN(MY_VALUE, b)的输出结果就是 MY_VALUEb。尽管MY_VALUE是个宏,你期待它展开成2b。 如何成为一个2b呢? 这么做:
#define JOIN(a, b) JOIN_EXPAND_PARAM(a,b)
#define JOIN_EXPAND_PARAM(a,b) a##b JOIN(MY_VALUE, b)的展开过程是:
1. JOIN(MY_VALUE, b)展开成 JOIN_EXPAND_PARAM(2, b)
2. JOIN_EXPAND_PARAM(2, b) 展开成 2b 这句话:Macro arguments are completely macro-expanded before they are substituted into a macro body, unless they are stringified or pasted with other tokens.
参考: http://gcc.gnu.org/onlinedocs/cpp/Argument-Prescan.html
**=======UPDATE=========**
C++11中引入了可变长参数模板,不需要用上面这么丑的方法了。几句话就搞定,而且不用带上说明参数个数的数字了:
// filename:template.cpp
#include <iostream>
using namespace std;
template<typename T>
void serialize(T value)
{
cout << value << endl;
}
template <typename Head, typename... Rail>
void serialize(Head head, Rail... rail)
{
cout << head << ",";
serialize(rail...);
}
int main(int argc, char *argv[])
{
serialize(1); // 输出:1
serialize(1, "hello"); // 输出:1,Hello
serialize(1, "hello", 'H'); // 输出:1,Hello,H
return 0;
}
编译的时候需要试用-std=c++0x或者 -std=gnu++0x
g++ -std=c++0x template.cpp -o template
标签:淫技,JOIN,serialize,C++,奇巧,ARG,const,type,define
From: https://blog.51cto.com/maray/6510867