实验任务一
task1：
程序源代码：
1 print(sum) 2 sum = 42 3 print(sum) 4 5 def inc(n): 6 sum = n+1 7 print(sum) 8 return sum 9 10 sum = inc(7) + inc(7) 11 print(sum)
运行结果：
实验任务二
task2-1
源代码：
1 def func1(a,b,c,d,e,f): 2 return [a,b,c,d,e,f] 3 4 def func2(a,b,c,*,d,e,f): 5 return [a,b,c,d,e,f] 6 7 def func3(a,b,c,/,d,e,f): 8 return [a,b,c,d,e,f] 9 10 print(func1(1,9,2,0,5,3)) 11 print(func1(a=1,b=9,c=2,d=0,e=5,f=3)) 12 print(func1(1,9,2,f=3,d=0,e=5)) 13 14 print(func2(11,99,22,d=0,e=55,f=33)) 15 print(func2(a=11,b=99,c=22,d=0,e=55,f=33)) 16 17 print(func3(111,999,222,0,555,333)) 18 print(func3(111,999,222,d=0,e=555,f=333))
运行结果：
line16 增加 print(func2(11,99,22,0,55,33))：
line18 增加 print(func3(a=111, b=999, c=222, 0, 555, 333) )
task2-2
源代码：
1 list1 = [1,9,8,4] 2 3 print(sorted(list1)) 4 print(sorted(list1,reverse = True)) 5 print(sorted(list1,True))
运行结果：
问题回答：sorted内置函数中，reverse必须按照关键字传递。
task2-3
源代码：
1 def func(a,b,c,/,*,d,e,f): 2 return([a,b,c,d,e,f]) 3 4 print(func(1,2,3,d=4,f=5,e=6))
运行结果：
实验任务三
task3
源代码：
1 def solve(a,b,c):
2 '''
3 求解一元二次方程, 返回方程的两个根
4
5 :para: a,b,c: float 方程系数
6 :return: tuple
7 '''
8 delta = b*b - 4*a*c
9 delta_sqrt = abs(delta)**0.5
10 p1 = -b/2/a
11 p2 = delta_sqrt/2/a
12
13 if delta > 0:
14 root1 = p1+p2
15 root2 = p1- p2
16
17 else:
18 root1 = complex(p1,p2)
19 root2 = complex(p1,-p2)
20
21 return root1,root2
22
23 while True:
24 try:
25 t = input('输入一元二次方程系数a b c, 或者，输入#结束:')
26 if t == '#':
27 print('结束计算，退出')
28 break
29 a,b,c = map(float,t.split())
30 if a == 0:
31 raise ValueError('a = 0, 不是一元二次方程')
32 except ValueError as e:
33 print(repr(e))
34 print()
35 except:
36 print('有其它错误发生\n')
37 else:
38 root1,root2 = solve(a,b,c)
39 print(f'root1 = {root1:.2f},root2 = {root2:.2f}')
40 print()
运行结果：
line23增加 print(solve.__doc__):
实验任务四
task4
源代码：
1 def list_genetator(q,z,b = 1): 2 lst = [] 3 while q <= z: 4 if q <= z+1: 5 lst.append(q) 6 q = q+b 7 else: 8 break 9 10 return lst 11 12 list1 = list_genetator(-5,5) 13 print(list1) 14 15 list2 = list_genetator(-5,5,2) 16 print(list2) 17 18 list3 = list_genetator(1,5,0.5) 19 print(list3)
运行结果：
实验任务五
task5
源代码：
1 def is_prime(n):
2 if n > 1:
3 if n%2 > 0:
4 return True
5 elif n == 2:
6 return True
7 else:
8 return False
9 else:
10 return False
11
12 s = [i for i in range(1,21)]
13 s_1 = []
14 s_2 = []
15 s_3 = {}
16 for j in s:
17 if is_prime(j) == True:
18 s_1.append(j)
19 for y in s:
20 if y > 2 and y%2 == 0:
21 s_2.append(y)
22 for i in range(len(s_2)):
23 for z in s_1:
24 for q in s_1:
25 if z + q == s_2[i]:
26 s_3.setdefault(s_2[i],(z,q))
27 for key,value in s_3.items():
28 a = value[0]
29 b = value[1]
30 print(f'{key} = {a}+{b}')
运行结果：
实验任务六
task6
源代码：
1 def encoder(s):
2 al = [chr(i) for i in range(97,123)]*2
3 al_m = [chr(i) for i in range(65,91)]*2
4 s_1 = list(s)
5 for j in s_1:
6 if j in al:
7 a = al.index(j)
8 a1 = s_1.index(j)
9 t = al[a+5]
10 s_1[a1] = t
11 elif j in al_m:
12 b = al_m.index(j)
13 b1 = s_1.index(j)
14 t = al_m[b+5]
15 s_1[b1] = t
16 else:
17 pass
18 s_s = ''.join(s_1)
19 return s_s
20
21 def decoder(text):
22 al = [chr(i) for i in range(97,123)]*2
23 al_m = [chr(i) for i in range(65,91)]*2
24 text_1 = list(text)
25 for j in text_1:
26 if j in al:
27 a = al.index(j)
28 a1 = text_1.index(j)
29 t = al[a-5]
30 text_1[a1] = t
31 elif j in al_m:
32 b = al_m.index(j)
33 b1 = text_1.index(j)
34 t = al_m[b-5]
35 text_1[b1] = t
36 else:
37 pass
38 text_s = ''.join(text_1)
39 return text_s
40
41
42
43
44 text = input('请输入英文文本：')
45
46 encoded_text = encoder(text)
47 print('编码后的文本：',encoded_text)
48
49 decoded_text = decoder(encoded_text)
50 print('对编码后的文本解码：',decoded_text)
运行结果：
说明：这个有点无能为力，知道为什么第二次测试结果不对的原因，因为替换后使用index函数只会获得列表中第一个出现该字母所对应的索引，但是暂时没想到解决办法。
实验任务七
task7
源代码：
1 def collatz(n):
2 s = []
3 for i in range(n**2):
4 s.append(n)
5 if n == 1:
6 break
7 else:
8 if n%2 == 0:
9 n = n/2
10 else:
11 n = n*3+1
12 return s
13
14
15 try:
16 n = eval(input('Enter an interger:'))
17 ans = collatz(n)
18 if n<=0:
19 raise ValueError('Error: n must be an interger')
20 except ValueError as e:
21 print(repr(e))
22 except:
23 print('Error: n must be an interger')
24 else:
25 print(ans)
运行结果：
实验任务八
task8
源代码：
1 def func(n):
2 if n == 0:
3 return 0
4 else:
5 return func(n-1)*2+1
6
7 while True:
8 x = input()
9 if x == '#':
10 print('计算结束')
11 break
12 n = int(x)
13 ans = func(n)
14 print(f'n = {n},ans = {ans}')
运行结果：
标签：return,函数,text,编程,al,实验,print,源代码,def From： https://www.cnblogs.com/wangyifan666/p/17427208.html