java引用类型传值

引用类型参数的传递，调用方的变量，和接收方的参数变量，地址指向的是同一个对象。
双方任意一方对这个对象的修改，都会影响对方
myself：这样也不用像php加&，说变就跟着变，会不会很麻烦，出现一些隐匿的bug

public class ImoocStudent {
    
    
    public void replaceFirstPlayer(String[] players,String playerName){
        System.out.println("将第一个球员替换:");
        players[0] = playerName;
    }
    
    public static void main(String[] args){
        String[] players = {"詹姆斯","科比","杜兰特","乔丹"};
        System.out.println("球队中现有球员:");
        for(String player : players){
            System.out.println(player + "\t");
        }
        System.out.println();
        
        ImoocStudent lei = new ImoocStudent();
        lei.replaceFirstPlayer(players,"job");
        
        System.out.println();
        for(String player : players){
            System.out.println(player + "\t");
        }
    }
    
    
}

• http://www.imooc.com/wiki/javalesson/javamethod.html