java对象和json字符串互转时名称不一样解决办法：@JsonProperty

@JsonProperty添加在属性上，并使用new ObjectMapper().writeValueAsString(object)转换为别名的JSON字符串

引入依赖

<dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-databind</artifactId>
            <version>2.13.3</version>
            <scope>compile</scope>
        </dependency>

创建实体类

import com.fasterxml.jackson.annotation.JsonProperty;
import lombok.Data;

@Data
public class DictVO {
    /**
     * 字典编号
     */
    @JsonProperty(value = "dict_type_id")
    private String dictTypeId;
    /**
     * 字典名称
     */
    @JsonProperty(value = "dict_type_name")
    private String dictTypeName;
    /**
     * 字典代码
     */
    @JsonProperty(value = "dict_type_code")
    private String dictTypeCode;

}

编写测试类

public class demo {
    public static void main(String[] args) throws JsonProcessingException {
        DictVO dictVO = new DictVO();
        dictVO.setDictTypeId("1745483801540300811");
        dictVO.setDictTypeCode("1");
        dictVO.setDictTypeName("激活");
        String s = JSON.toJSONString(dictVO);
        System.out.println(s);
        DictVO dictVO1 = JSON.parseObject(s, DictVO.class);
        System.out.println(dictVO1);
    }
}

结果：

{"dict_type_code":"1","dict_type_id":"1745483801540300811","dict_type_name":"激活"}
DictVO(dictTypeId=1745483801540300811, dictTypeName=激活, dictTypeCode=1)