【2020团体程序设计天梯赛】L1部分（PTA，L1-065到L1-072）题解代码

概要

• L1一共8题，5分，10分，15分，20分各两题。
• 5分题一般会输入输出就行，10分题就是一个循环或者选择结构
• 15分题有简单的模拟和查找，20分题是稍微繁琐的简单模拟这样。

L1-065 嫑废话上代码 (5分)

#include<bits/stdc++.h>
using namespace std;
int main(){
  cout<<"Talk is cheap. Show me the code.";
  return 0;
}

L1-066 猫是液体 (5分)

#include<bits/stdc++.h>
using namespace std;
int main(){
  int a, b, c;
  cin>>a>>b>>c;
  cout<<a*b*c;
  return 0;
}

L1-067 洛希极限 (10分)

#include<bits/stdc++.h>
using namespace std;
int main(){
  float a, b, c; int d;
  cin>>a>>d>>b;
  if(d==0){
    c = a*2.455;
  }else{
    c = a*1.26;
  }
  printf("%.2f ",c);
  if(c<b)cout<<"^_^";
  else cout<<"T_T";
  return 0;
}

L1-068 调和平均 (10分)

#include<bits/stdc++.h>
using namespace std;
int main(){
  int n;  cin>>n;
  float ans;
  for(int i = 1; i <= n; i++){
    float x;  cin>>x; 
    ans += 1.0/x;
  }
  ans /= n;
  ans = 1.0/ans;
  printf("%.2f",ans);
  return 0;
}

L1-069 胎压监测 (15分)

#include<bits/stdc++.h>
using namespace std;
int main(){
  int a[10], bj, yz;
  int mx=-1;
  for(int i=1;i<=4;i++){cin>>a[i];mx=max(mx,a[i]);}
  cin>>bj>>yz;
  
  int ok = 1, lq;
  for(int i = 1; i <= 4; i++){
    if(mx-a[i]>yz || a[i]<bj){
      if(ok==1)ok=0;
      else ok = 2;
      lq = i;
    }
  }
  if(ok==1)cout<<"Normal\n";
  else if(ok==0)cout<<"Warning: please check #"<<lq<<"!\n";
  else cout<<"Warning: please check all the tires!\n";
  
  return 0;
}

L1-070 吃火锅 (15分)

#include<bits/stdc++.h>
using namespace std;
int main(){
  string s;
  int n=0, fs=0, cnt=0;
  while(getline(cin,s)){
    if(s==".")break;
    n++;
    if(s.find("chi1 huo3 guo1")!=string::npos){
      if(cnt==0)fs=n;
      cnt++;
    }
  }
  cout<<n<<"\n";
  if(cnt!=0)cout<<fs<<" "<<cnt<<endl;
  else cout<<"-_-#\n";
  return 0;
}

L1-071 前世档案 (20分)

#include<bits/stdc++.h>
using namespace std;
int main(){
  int n, m;  cin>>n>>m;
  for(int i = 1; i <= m; i++){
    string s;  cin>>s;
    int p = 0;
    for(int j = 0; j < s.size(); j++){
      if(s[j]=='y')p = p<<1;
      else p = p<<1|1;
    }
    cout<<p+1<<"\n";
  }
  return 0;
}

L1-072 刮刮彩票 (20分)

#include<bits/stdc++.h>
using namespace std;

int a[10][10], b[10], bx,by,bz;
int num[] = {0,1,2,3,4,5,10000,36,720,360,80,252,108,72,54,180,72,180,119,36,306,1080,144,1800,3600};
int main(){
  for(int i = 1; i <= 3; i++){
    for(int j = 1; j <= 3; j++){
      cin>>a[i][j];
      b[a[i][j]]++;
      if(a[i][j]==0){
        bx = i; by = j;
      }
    }
  }
  for(int i = 1; i <= 9; i++)
    if(b[i]==0)bz=i;
  a[bx][by]=bz;
  for(int i = 1; i <= 3; i++){
    int x, y;  cin>>x>>y;
    cout<<a[x][y]<<"\n";
  }
  int fx;  cin>>fx;
  int ans = 0;
  for(int i = 1; i <= 3; i++){
    if(fx<=3)ans += a[fx][i];
    else if(fx<=6)ans += a[i][fx-3];//WA2
    else if(fx==7)ans += a[i][i];
    else ans += a[i][3-i+1];
    
  }
  cout<<num[ans];
  return 0;
}