Java中计算两个时间相差多少天，时，分，秒

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.time.LocalDate;
import java.util.Date;

String strTime1 = "2020-12-04 12:20:20";
String strTime2 = "2020-12-03 14:20:20";
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date1;
Date date2;
try {
      date1 = format.parse(strTime1);
      date2 = format.parse(strTime2);
      long lDate1 = date1.getTime();
      long lDate2 = date2.getTime();
      long diff = (lDate1 < lDate2) ? (lDate2 - lDate1) : (lDate1 - lDate2);
      long day = diff / (24 * 60 * 60 * 1000);
      long hour = diff / (60 * 60 * 1000) - day * 24;
      long min = diff / (60 * 1000) - day * 24 * 60 - hour * 60;
      long sec = diff / 1000 - day * 24 * 60 * 60 - hour * 60 * 60 - min * 60;
      System.out.println("date1 与 date2 相差 " + day + "天" + hour + "小时" + min + "分" + sec + "秒");
    }
catch (ParseException e) {
      e.printStackTrace();
    }

运行结果如下：

 注：上述代码用于传入的两个时间为String类型的，如果传入时间直接为Date类型的，可做适当调整。

 参考博客：

https://www.cnblogs.com/mforestlaw/p/3289414.html