L 小沙の抱团 hard
代码
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#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<vector>
#include<queue>
using namespace std;
#define X first
#define Y second
typedef pair<int,int> pii;
typedef long long LL;
const char nl = '\n';
const int N = 1e5+10;
const int M = 1e6+10;
int n,m;
int b[N],x[N];
LL dp[N];
void solve(){
cin >> n >> m;
memset(dp,0x3f,sizeof dp);
dp[n] = 0;
for(int i = 1; i <= m; i ++)cin >> b[i] >> x[i];
for(int i = n; i >= 1; i --){
for(int j = 1; j <= m; j ++){
if(i%x[j] && i >= i % x[j])dp[i-i%x[j]] = min(dp[i-i%x[j]],dp[i] + b[j]);
}
}
for(int i = 1; i <= n; i ++){
if(dp[i] != dp[1]){
cout << dp[i];
return;
}
}
cout << 0; //别漏了特殊情况
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0),cout.tie(0);
solve();
}
注意
- 找到正确的状态转移方程很重要