第454题.四数相加II
class Solution {
public:
int fourSumCount(vector<int>& nums1, vector<int>& nums2, vector<int>& nums3, vector<int>& nums4) {
unordered_map<int,int> ma;
int target = 0;
int num = 0;
for (auto i : nums1) {
for (auto j : nums2) {
ma[i+j]++;
}
}
for (auto i : nums3) {
for (auto j : nums4) {
target = 0-(i+j);
if(ma.find(target) != ma.end()) num += ma[target];
}
}
return num;
}
};
383. 赎金信
class Solution {
public:
bool canConstruct(string ransomNote, string magazine) {
int num[26] = {0};
for (int i = 0; i < magazine.size(); ++i) {
num[magazine[i] - 'a']++;
}
for (int j = 0; j < ransomNote.size(); ++j) {
if (num[ransomNote[j] - 'a'] != 0) num[ransomNote[j] - 'a']--;
else return false;
}
return true;
}
};
第15题. 三数之和
class Solution {
public:
vector<vector<int>> threeSum(vector<int>& nums) {
sort(nums.begin(),nums.end());
vector<vector<int>> result;
for (int i = 0; i < nums.size(); ++i) {
if(nums[i] > 0) break; // 大于零直接退出
if(i > 0 && nums[i] == nums[i-1]) continue;
int left = i + 1;
int right = nums.size() - 1;
while(left < right) {
int sum = nums[i] + nums[left] + nums[right];
if (sum > 0) right--;
else if (sum < 0) left++;
else {
result.push_back(vector<int>({nums[i],nums[left],nums[right]}));
while((left < right)&& nums[left] == nums[left+1]) left++;
while((left < right)&& nums[right] == nums[right-1]) right--;
left++;
right--;
}
}
}
return result;
}
};
第18题. 四数之和
class Solution {
public:
vector<vector<int>> fourSum(vector<int>& nums, int target) {
sort(nums.begin(),nums.end());
vector<vector<int>> result;
for (int i = 0; i < nums.size(); ++i) {
if(nums[i] > target && nums[i] > 0) break; // 剪枝
if (i > 0 && nums[i] == nums[i-1]) continue; // 去重
for (int j = i+1; j < nums.size();++j) {
if (nums[i] + nums[j] > target && nums[i] + nums[j] > 0) break;
if (j > i +1 && nums[j] == nums[j-1]) continue;
int left = j + 1;
int right = nums.size() - 1;
while(left < right) {
long sum = (long)nums[i] + nums[j] + nums[left] + nums[right];
if (sum > target) right--;
else if (sum < target) left++;
else {
result.push_back(vector<int>({nums[i],nums[j],nums[left],nums[right]}));
while((left < right)&& nums[left] == nums[left+1]) left++;
while((left < right)&& nums[right] == nums[right-1]) right--;
left++;
right--;
}
}
}
}
return result;
}
};
标签:vector,right,nums,int,随想录,++,四数,两数,left
From: https://www.cnblogs.com/masene/p/17058037.html