1、list<dto>
List<CollectionItemsTemp> itemsList = new ArrayList<>(); List<String> nameList = new ArrayList<>(); if (ToolUtil.isNotEmpty(itemsList) && itemsList.size() > 0){ nameList = itemsList.stream().collect(Collectors.groupingBy(CollectionItemsTemp::getShortName, Collectors.counting())) .entrySet().stream().filter(e -> e.getValue() > 1) .map(Map.Entry::getKey).collect(Collectors.toList()); } if (ToolUtil.isNotEmpty(nameList) && nameList.size()>0){ sj.add("表格中存在重复..称:"+nameList.toString()); return new Resp(HttpStatus.INTERNAL_SERVER_ERROR.value(), sj.toString(), null); }
2、list<String>
List<String> telephoneList = new ArrayList<>(); //字符串取出重复值 List<String> repeatList = telephoneList.stream().collect(Collectors.groupingBy(e -> e, Collectors.counting())) .entrySet().stream().filter(e -> e.getValue() > 1) .map(Map.Entry::getKey).collect(Collectors.toList());
3、
List<FeYltTicketBatchReq.IssueTicketInfo> issueTicketInfo = issueTicket.getIssueTicketInfo(); //每个人的服务券数量相加 int sum = issueTicketInfo.stream().mapToInt(FeYltTicketBatchReq.IssueTicketInfo::getTicketCount).sum();
标签:nameList,Java,Collectors,stream,重复,List,获取,new,itemsList From: https://www.cnblogs.com/zhaoyijunjava/p/16647038.html