合并k个有序列表-python

主要思路：借鉴堆、队列特点，构建新的有序结果

# merge the k sorted list
# main idea: 将每个list放入队列，初始一个小顶堆，size为list个数，value为队列的首个元素，交替寻找最小值存储到新list中
import heapq
from collections import deque
nums = [[1,3,43], [16,29,89], [4, 33, 88, 100,1011]]
# 队列化
queues = list(map(deque, nums))
heap = []
for i, q in enumerate(queues):
    heap.append((q.popleft(), i))
# 堆化，弹出最小值：
heapq.heapify(heap)
result = []
while heap:
    # 弹出最小元素
    val, index = heapq.heappop(heap)
    result.append(val)
    # 找出弹出元素所在队列中的下一个元素，push到堆中，重复以上步骤
    if queues[index]:
        new_num = queues[index].popleft()
        heapq.heappush(heap, (new_num, index))
result

参考：https://izsk.me/2019/03/02/%E5%90%88%E5%B9%B6K%E4%B8%AA%E6%9C%89%E5%BA%8F%E6%95%B0%E7%BB%84(python)/