JavaScript获取某个时间到n天前时间组成的数组

代码

getLastNDay (time, n, type = '') {
    let arry = []
    for (let i = 0; i < n; i++) {
      let date = new Date(time)
      date.setDate(date.getDate() - i)
      let year = date.getFullYear()
      let mon = date.getMonth() + 1 < 10 ? '0' + (date.getMonth() + 1) : date.getMonth() + 1
      var d = date.getDate() < 10 ? '0' + date.getDate() : date.getDate()
      arry.push(year + type + mon + type + d)
    }
    return arry.reverse()
  }

getLastNDay(2022-01-01,5)//['20211228', '20211229', '20211230', '20211231', '20220101']
getLastNDay(2022-01-01,5,'/')//['2021/12/28', '2021/12/29', '2021/12/30', '2021/12/31', '2022/01/01']