题目:
编写代码,移除未排序链表中的重复节点。保留最开始出现的节点。
示例1:
输入:[1, 2, 3, 3, 2, 1]
输出:[1, 2, 3]
示例2:
输入:[1, 1, 1, 1, 2]
输出:[1, 2]
代码实现:
class Solution {标签:yyds,head,ListNode,金典,pos,next,移除,null,节点 From: https://blog.51cto.com/u_13321676/5916448
public ListNode removeDuplicateNodes(ListNode head) {
if (head == null) {
return head;
}
Set<Integer> occurred = new HashSet<Integer>();
occurred.add(head.val);
ListNode pos = head;
// 枚举前驱节点
while (pos.next != null) {
// 当前待删除节点
ListNode cur = pos.next;
if (occurred.add(cur.val)) {
pos = pos.next;
} else {
pos.next = pos.next.next;
}
}
pos.next = null;
return head;
}
}