一 类图
二 构造方法
public SynchronousQueue() {
this(false);
}
/**
* Creates a {@code SynchronousQueue} with the specified fairness policy.
*
* @param fair if true, waiting threads contend in FIFO order for
* access; otherwise the order is unspecified.
*/
public SynchronousQueue(boolean fair) {
this.transferer = fair ? new TransferQueue<E>() : new TransferStack<E>();
}
默认的使用栈实现,我们就跟进TransferStack
三 类结构
/**
* 抽象里面就一个方法 通过e是不是null判定线程是put线程还是take线程
* - e有值 put线程
* - e为null take线程
*/
abstract E transfer(E e, boolean timed, long nanos);
TransferStack和TransferQueue都是Transfer的实现,只声明了一个方法
三 API
1 put
public void put(E e) throws InterruptedException {
if (e == null) throw new NullPointerException();
if (transferer.transfer(e, false, 0) == null) {
Thread.interrupted();
throw new InterruptedException();
}
}
2 take
public E take() throws InterruptedException {
E e = transferer.transfer(null, false, 0);
if (e != null)
return e;
Thread.interrupted();
throw new InterruptedException();
}
3 transfer
/**
* 通过e是不是null判定线程是put线程还是take线程
* - e有值 put线程
* - e为null take线程
* 不管是put还是take都会将其数据(e或者null)封装为节点放到栈上 移动head指针模拟出元素入栈
* 通过节点中的mode不同体现出职责
* - put的mode是data
* - take的mode是request
* 封装入栈的节点根据既有的栈顶节点mode状态决定自己的mode和行为
* - 直接入栈型
* - 空栈
* - 栈顶节点跟自己一样mode 不互补
* - 交易型
* - 跟栈顶节点互补 可以交易
* - 帮助交易型
* - 栈上两个节点正在交易 帮他们加速
*/
@SuppressWarnings("unchecked")
E transfer(E e, boolean timed, long nanos) {
/*
* Basic algorithm is to loop trying one of three actions:
*
* 1. If apparently empty or already containing nodes of same
* mode, try to push node on stack and wait for a match,
* returning it, or null if cancelled.
*
* 2. If apparently containing node of complementary mode,
* try to push a fulfilling node on to stack, match
* with corresponding waiting node, pop both from
* stack, and return matched item. The matching or
* unlinking might not actually be necessary because of
* other threads performing action 3:
*
* 3. If top of stack already holds another fulfilling node,
* help it out by doing its match and/or pop
* operations, and then continue. The code for helping
* is essentially the same as for fulfilling, except
* that it doesn't return the item.
*/
SNode s = null; // constructed/reused as needed
/**
* put线程初始状态 请求交易还没交付的生产者
* take线程初始状态 请求交易还没匹配的消费者
*/
int mode = (e == null) ? REQUEST : DATA;
for (;;) {
SNode h = this.head; // 栈顶节点
if (h == null || h.mode == mode) { // empty or same-mode // 交易栈为空或者交易栈顶节点和新节点模式一样 新节点作为栈顶入栈等待被交易
if (timed && nanos <= 0L) { // can't wait
if (h != null && h.isCancelled())
casHead(h, h.next); // pop cancelled node
else
return null;
} else if (this.casHead(h, s = snode(s, e, h, mode))) { // 新节点为栈顶
SNode m = awaitFulfill(s, timed, nanos);
if (m == s) { // wait was cancelled
clean(s);
return null;
}
if ((h = head) != null && h.next == s)
casHead(h, s.next); // help s's fulfiller
return (E) ((mode == REQUEST) ? m.item : s.item);
}
} else if (!isFulfilling(h.mode)) { // try to fulfill // 栈顶节点没处在交易中 尝试跟栈顶节点进行交易
if (h.isCancelled()) // already cancelled // 栈顶节点无效了弹出 所谓弹出就是将栈顶指针移向栈顶的下一个节点
casHead(h, h.next); // pop and retry
else if (casHead(h, s=snode(s, e, h, FULFILLING|mode))) { // 入栈新节点 栈顶mode集合加上交易中 用交易中标识栈顶节点
for (;;) { // loop until matched or waiters disappear
SNode m = s.next; // m is s's match // 栈上前2个节点交易
if (m == null) { // all waiters are gone
casHead(s, null); // pop fulfill node
s = null; // use new node next time
break; // restart main loop
}
SNode mn = m.next;
/**
* s是栈顶节点
* - 当初已经有线程因为等待交易而阻塞 线程记录在s的waiter中
* - s中的mode集合包含了正在交易
* m是第二个节点
* - m对应的线程还没当作阻塞线程记录到m的waiter上 线程正在进行这交易行为
*/
if (m.tryMatch(s)) {
casHead(s, mn); // pop both s and m // 栈上前2个节点匹配成功 弹出
return (E) ((mode == REQUEST) ? m.item : s.item);
} else // lost match
s.casNext(m, mn); // help unlink
}
}
} else { // help a fulfiller // 栈顶节点正在交易中 帮他们两个节点交易加速
SNode m = h.next; // m is h's match
if (m == null) // waiter is gone
casHead(h, null); // pop fulfilling node
else {
SNode mn = m.next;
if (m.tryMatch(h)) // help match
casHead(h, mn); // pop both h and m
else // lost match
h.casNext(m, mn); // help unlink
}
}
}
}
标签:java15,SynchronousQueue,源码,线程,mode,put,null,节点,take
From: https://www.cnblogs.com/miss-u/p/16923842.html