1.十进制到n进制的转换(n<10)原因：不知道如何实现A~F的输出。原代码，只能实现到n进制，n<10#include<stdio.h>#include<stdlib.h>intmain(){intnewbase,num,q=1,r,newnum=0,count=1,i;printf("thenewbase:");scanf("%d",&newbase);

用C语言实现下面伪代码描述的进制转换程序，提交运行结果截图，至少三张，包含转换为二进制，八进制，十六进制的截图#include<stdio.h>#include<stdlib.h>intmain(void){in

include<stdio.h>intmain(){intnumber,newbase;//number为十进制数，newbase为目标进制大小printf("Inputnumber:\n");scanf("%d",&number);printf("Inputnewbase

伪代码Write"Enterthenewbase"ReadnewBaseWrite"Enterthenumbertobeconverted"ReaddecimalNumberSetquotientto1WHILE(quotientisnotzero) Set