/*题意：给n求满足i*j+i+j=n(0<i<=j)方案数思路：xy+x+y=n(x+1)(y+1)=x*y+x+y+1=n+1;即求n+1的因子对数参考：https://blog.csdn.net/Puppettt/article/details/83030925?ops_request_misc=%257B%2522request%255Fid%2522%253A%25221720964219168001821369