• 2024-09-01题解:AT_abc257_d [ABC257D] Jumping Takahashi 2
    [ABC257D]JumpingTakahashi2博客食用更佳:Myblog。大体思路这题是一道二分题,因为\(S\)越大,就越容易满足题目要求,\(S\)越小,就越难满足题目要求,符合二分的特点。下面先贴上二分代码。LLl=0,r=1e10;while(l<r){intmid=l+r>>1;if(check(mid))