水水水~题目链接戳我分析首先根据题目条件可得式子=>\((x-2)(y-2)=n(2x+2y-4)\)化简式子可得\[\begin{align}(x-2)(y-2)=&n(2x+2y-4)\\xy-2x-2y+4=&2nx+2ny-4n\\x(y-2n-2)=&2ny-4n-4+2y\\x=&\frac{2ny-4n-4