###A.```c++#include<bits/stdc++.h>usingnamespacestd;constintN=1e6+7;voidsolve(){  intx;  cin>>x;  cout<<x/10+x%10<<endl;}intmain(){  intT;  cin>>T;  while(T--)solve();

CodeforcesRound964(Div.4)标题CodeForces1999A.A+BAgain?时限1second空限256megabytes题目描述给定一个两位数的正整数\(n\)，求其数字之和。输入第一行包含一个整数\(t\)（\(1\leqt\leq90\)）——测试用例的数量。每个测试用例的唯一一行包含一个两位数的正

这场的题不错,就是一直在inqueue

知识点1.对于两个数字，一个乘n，一个除以n，可以理解为n进制下的这个数乘10和除10。比如E题用这个知识点就可以很快的解决问题。题解A.A+BAgain?#include<bits/stdc++.h>#defineintlonglongusingnamespacestd;voidsolve(){ strings; cin>>s; cout<<s[0]-'0'+s[1]-

CodeforcesRound964(Div.4)A送分B大意:两个人两张牌随机翻求a翻出来的牌比b大的可能#include<cstdio>#include<cmath>#include<algorithm>#include<iostream>#include<cstring>#include<vector>#defineepemplace_backusingnamespace

题目链接:https://codeforces.com/contest/1999/problem/D题目描述Slavic的考试非常难，需要您的帮助才能通过。以下是他正在努力解决的问题：存在一个字符串s，它由小写英文字母和可能零个或多个“？”组成。Slavic被要求将每个“？”更改为小写英文字母，使得字符串t成为字符串s的

D.Slavic'sExamtimelimitpertest:2secondsmemorylimitpertest:256megabytesinput:standardinputoutput:standardoutputSlavichasaverytoughexamandneedsyourhelpinordertopassit.Hereisthequestionheisstrugglingwith:Ther

C.Showeringtimelimitpertest:2secondsmemorylimitpertest:256megabytesinput:standardinputoutput:standardoutputAsacomputersciencestudent,Alexfacesahardchallenge —showering.Hetriestoshowerdaily,butdespitehisbestefforts

比赛链接：CodeforcesRound964(Div.4)A思路    水题代码#include<iostream>usingnamespacestd;#definelllonglonginlineintread(void){intx=0,f=1;charch=getchar();while(ch<'0'||ch>'9'){

A.A+BAgain?timelimitpertest:1secondmemorylimitpertest:256megabytesinput:standardinputoutput:standardoutputGivenatwo-digitpositiveinteger\(n\),findthesumofitsdigits.InputThefirstlinecontainsaninteger\(t\)(\(1

难绷事实：Bwa一发A......#include<bits/stdc++.h>#definepbpush_back#defineintlonglongusingnamespacestd;constintN=500100;inta[N];signedmain(){intT;cin>>T;while(T--){intn;cin>>n;strings=

CodeforcesRound964(Div.4)A计算数位和。voidsolve(){ inta=0,n; cin>>n; while(n)a+=n%10,n/=10; cout<<a<<'\n';}B模拟，直接枚举4种出牌顺序，按题目给的规则判断即可。boolchk(intx1,inty1,intx2,inty2){ intc1=(x1&g