在编码过程中将正确的括号放在正确的位置

在下面的计算机代码中插入圆括号，使变量 x 的值对应于以下公式：

import math
x=math.sqrt(1535) + 3 / 1 - math.exp(-2) ** 2 % 336030 / 345

import math

# Calculate the inner term (under the square root)
inner_term = math.sqrt(1535) + 3 / (1 - math.exp(-2))

# Square the entire inner term
x_squared = inner_term ** 2

# Calculate the modulo
modulo_result = x_squared % (336030 / 345)

# Print the result
print(f"The value of x is approximately {modulo_result:.2f}")

import math
x = (((math.sqrt(1535) + 3) / (1 - math.exp(-2))) ** 2 % 336030) / 345

This line of code calculates the value of x according to the formula you provided. Here's a breakdown of the parenthesis placement:

1. (math.sqrt(1535) + 3) : Calculates the sum of the square root of 1535 and 3.
2. (1 - math.exp(-2)) : Calculates the result of 1 minus the exponential of -2.
3. ((math.sqrt(1535) + 3) / (1 - math.exp(-2))) : Divides the result from step 1 by the result from step 2.
4. (((math.sqrt(1535) + 3) / (1 - math.exp(-2))) ** 2 : Squares the result from step 3.
5. (((math.sqrt(1535) + 3) / (1 - math.exp(-2))) ** 2 % 336030) : Calculates the remainder when the result from step 4 is divided by 336030.
6. ((((math.sqrt(1535) + 3) / (1 - math.exp(-2))) ** 2 % 336030) / 345) : Divides the result from step 5 by 345, giving the final value of x .

This ensures that the operations are performed in the correct order of operations (PEMDAS/BODMAS).