首页 > 编程问答 >OSError(22, '无效参数') - 无法打开任何 `.ipynb` 和 `.py` 文件

OSError(22, '无效参数') - 无法打开任何 `.ipynb` 和 `.py` 文件

时间:2024-07-24 13:08:56浏览次数:11  
标签:python jupyter-notebook jupyter-lab

我无法打开我过去拥有的任何 Jupyernotebook 或 python 文件,并且收到此错误:

Unreadable Notebook: C:\Users\[mypath]\main\main.ipynb OSError(22, 'Invalid argument')

[mypath] 是我从上面删除的目录的一部分。

我尝试通过 解决方案这篇文章 ,但仍然有同样的问题。

这也是我打开 .py 文件

Error! Traceback (most recent call last):
File "C:\Users\moham\anaconda3\lib\site-packages\tornado\web.py", line 1704, in _execute
result = await result
File "C:\Users\moham\anaconda3\lib\site-packages\tornado\gen.py", line 234, in wrapper
yielded = ctx_run(next, result)
File "C:\Users\moham\anaconda3\lib\site-packages\notebook\services\contents\handlers.py", line 111, in get
model = yield maybe_future(self.contents_manager.get(
File "C:\Users\moham\anaconda3\lib\site-packages\notebook\services\contents\filemanager.py", line 444, in get
model = self._file_model(path, content=content, format=format)
File "C:\Users\moham\anaconda3\lib\site-packages\notebook\services\contents\filemanager.py", line 371, in
_file_model
content, format = self._read_file(os_path, format)
File "C:\Users\moham\anaconda3\lib\site-packages\notebook\services\contents\fileio.py", line 306, in
_read_file
bcontent = f.read()
OSError: [Errno 22] Invalid argument

通过jupyterlab打开文件时遇到的错误。


The error message "OSError(22, 'Invalid argument')" usually indicates an issue with the filename or path you're trying to access, especially if it's happening with both .ipynb and .py files.

Here's a breakdown of common causes and solutions:

1. Special Characters in File or Directory Names:

  • Issue: File or directory names containing invalid characters (like ? , * , : , < , > , | , \ ) can confuse the file system.
  • Solution: Rename any files or directories within the path that contain these characters. Replace them with underscores or other allowed symbols.

2. File Path Length Limitations:

  • Issue: Windows has a maximum path length limit (around 260 characters). Exceeding this can cause errors.
  • Solution:
    • Shorten the Path: Try moving your project to a directory with a shorter path (e.g., C:\Projects\your_project ).
    • Enable Long Path Support (Windows 10+):
      1. Open "Local Group Policy Editor" (gpedit.msc).
      2. Navigate to "Computer Configuration" -> "Administrative Templates" -> "System" -> "Filesystem".
      3. Enable the "Enable Win32 long paths" policy.
      4. Restart your computer.

3. File Permissions:

  • Issue: If you don't have the necessary read permissions on the files or directories, you might encounter this error.
  • Solution:
    1. Right-click on the affected folder containing your files.
    2. Select "Properties" -> "Security" tab.
    3. Check if your username has "Read" permission. If not, click "Edit" and grant the appropriate permissions.

4. Corrupted Jupyter Notebook or Python Files:

  • Issue: The files themselves could be corrupted.
  • Solution:
    • Try opening with a text editor: If possible, open the .ipynb file in a plain text editor to see if there are any obvious issues with the JSON structure.
    • Create a new file: If you can open other notebooks but not specific ones, try creating a new notebook and copying the code (if possible) from the problematic one.

5. Issues with Jupyter Notebook Installation:

  • Issue: A corrupted or misconfigured Jupyter installation can lead to problems.
  • Solution:
    • Reinstall Jupyter Notebook: Try uninstalling and then reinstalling Jupyter Notebook: bash pip uninstall jupyter notebook pip install jupyter notebook

Additional Tips:

  • Restart: Sometimes a simple restart of your computer can resolve temporary glitches.
  • Run as Administrator: Try running Jupyter Notebook or your Python scripts as administrator to rule out any permission issues.

If none of these solutions work, please provide the following information for further assistance:

  • Operating System: (e.g., Windows 10, macOS, Linux)
  • Jupyter Notebook Version: (run jupyter --version in your terminal/command prompt)
  • Python Version: (run python --version in your terminal/command prompt)
  • Exact filename and path: (share the full path of one of the files you're trying to open)

标签:python,jupyter-notebook,jupyter-lab
From: 78786430

相关文章

  • Python用shp文件裁剪多个遥感影像的方法
      本文介绍基于Python中ArcPy模块,基于矢量数据范围,对大量栅格遥感影像加以批量裁剪掩膜的方法。  首先,话不多说,本文所需要的代码如下所示。#-*-coding:utf-8-*-"""CreatedonTueDec1320:07:482022@author:fkxxgis"""importarcpyfromarcpy.saimport*......
  • 以编程方式删除 Python 源中的类型提示
    我有一些为Python3.5编写的源代码,我想使其在Python3.4下可执行。我使用的3.5中唯一在3.4中不可用的功能是类型提示,因此我想编写一个脚本来完全删除这些功能。乍一看这似乎很容易,我决定编写一些正则表达式这样做,但后来我想到了一些边缘情况,我不确定如何解决像这样的......
  • Python 类型暗示​​一个充满 myclass 对象的双端队列
    使用Python3.6或更高版本,我想输入提示一个返回MyClass对象的函数myfunc我如何提示myqueue是一个deque|||充满MyClass对象?objects?fromcollectionsimportdequeglobal_queue=deque()classMyClass:passdefmyfunc(m......
  • python之名称空间和作用域(关键字:global和nonlocal的使用)
    文章目录前言1、名称空间和作用域1.1引言1.2名称空间1.2.1内置名称空间1.2.2全局名称空间1.2.3局部名称空间1.2.4名称空间的产生和销毁顺序1.3作用域1.3.1全局作用域1.3.2局部作用域1.3.3名字的查找顺序1.4关键字:global1.5关键字:nonlocal前言本篇文章......
  • 用于 isinstance() 检查的 dict_keys 的显式 python3 类型是什么?
    在Python3中,我应该使用什么类型来检查字典键是否属于它?>>>d={1:2}>>>type(d.keys())<class'dict_keys'>所以我很自然地尝试了这个:>>>isinstance(d.keys(),dict_keys)Traceback(mostrecentcalllast):File"<stdin>",......
  • 初学Python时需要认识清楚的几个概念:对象、函数、圆括号给、点取、方括号取
    这是我在自学Python的过程中自己挑选和提炼出来的几个重要的概念,之所以特意介绍这些概念,其中包含了我自己的思维方式和我对Python设计理念的认识,有其独特性和局限性。我希望这篇文章能够给喜爱Python的朋友们带来一些启发。1、对象(Object)对象是Python编程的基本单元。就像音是......
  • 如何接受文件或路径作为python中方法的参数
    我正在尝试编写一个方法,该方法将接受打开的文件myFile=open("myFile.txt")obj.writeTo(myFile)myFile.close()或带有路径的字符串obj.writeTo("myFile.txt")该方法的实现如下:defwriteTo(self,hessianFile):ifisinstance(hessianFile,file):pr......
  • Python,“pathlib.Path.open()”方法和内置函数“open()”不返回“typing.IO”的实例
    我读过一些其他答案,它们似乎与现实生活中发生的事情相矛盾。尝试以下操作:fromtypingimportIOfrompathlibimportPathexample_path=Path(r"D:\Example.txt")withexample_path.open("r")asf:print(isinstance(f,IO))withopen(example_path)a......
  • 【Dison夏令营 Day 28】用 Python 创建恐龙游戏
    谁没有玩过谷歌著名的“恐龙游戏”?也许每个人都玩过这个游戏。今天,在这篇文章中,我们将帮助你用Python开发一个恐龙游戏。本教程将深入讲解每一行代码,并提供参考资料。我们将尽力让读者详细、透彻地理解这个项目。Python版恐龙游戏的任务记录包括图片文档和Python资料......
  • Python 无法 pickle 自定义类型
    我正在尝试在ProcessPool中运行一个函数,该函数将通过读取python文件并运行生成的类中的方法来加载一些自定义类。我遇到的错误是TypeError:cannotpickle'generator'object该方法需要返回一个生成器。我该如何解决这个问题,谢谢。我用谷歌搜索但没有运气。......