# !/usr/bin/python3标签:30,第几天,isLeapYear,31,year,day,某日,某年某月,Sum From: https://www.cnblogs.com/DreamTalk/p/16868053.html
# *_*coding:utf8 *-*
# @Time :2022-11-08
# @Author :jeck
# @Email :
# @File :question4.py
# 输入某年某月某日,判断这一天是这一年的第几天
year = int(input('输入年:'))
month = int(input('输入月:'))
day = int(input('输入日:'))
day_Sum = 0
isLeapYear = False # 是否是闰年。
if year % 4 == 0:
if year % 100 != 0:
isLeapYear = True
elif year % 400 == 0:
isLeapYear = True
else:
isLeapYear = False
Month_day = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
for i in range(month):
day_Sum += Month_day[i]
day_Sum += day
if isLeapYear:
day_Sum += 1
print (day_Sum)