编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。
不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
示例 1:
输入:s = ["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:
输入:s = ["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
提示:
1 <= s.length <= 105
s[i] 都是 ASCII 码表中的可打印字符
方法一:双指针
1 /** 2 * @param {character[]} s 3 * @return {void} Do not return anything, modify s in-place instead. 4 */ 5 var reverseString = function(s) { 6 const n =s.length; 7 for(let left =0,right=n-1;left<right;++left,--right){ 8 [s[left],s[right]]=[s[right],s[left]]; 9 } 10 };
标签:示例,反转,344,数组,字符串,输入 From: https://www.cnblogs.com/icyyyy/p/16850645.html