任务四
#include <stdio.h>
#include<stdlib.h>
#define N 10
typedef struct {
char isbn[20]; // isbn号
char name[80]; // 书名
char author[80]; // 作者
double sales_price; // 售价
int sales_count; // 销售册数
} Book;
void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);
int main() {
Book x[N] = {
{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
{"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49, 30},
{"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
{"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
{"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
{"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
{"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基",22.5, 44},
{"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118,42},
{"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
printf("图书销量排名(按销售册数): \n");
sort(x, N);
output(x, N);
printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
system("pause");
return 0;
}
void output(Book x[], int n){
int i=0;
printf("%-20s%-30s%-20s%-10s%-10s","ISBN号","书名","作者","售价","销售册数\n");
for(i = 0;i<n;i++){
printf("%-20s%-30s%-20s%-10.1lf%-10d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
}
}
void sort(Book x[], int n){
int b=0,i = 0;
Book t;
for(b=0;b<n;b++){
for(i=0;i<n-1;i++){
if(x[i].sales_count<x[i+1].sales_count){
t = x[i];
x[i] = x[i+1];
x[i+1] = t;
}
}
}
}
double sales_amount(Book x[], int n){
double sum = 0;
int i=0;
for(i=0;i<n;i++){
sum += x[i].sales_count * x[i].sales_price;
}
return sum;
}
任务五
#include <stdio.h>
#include<stdlib.h>
typedef struct {
int year;
int month;
int day;
} Date;
void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);
void test1() {
Date d;
int i;
printf("输入日期:(以形如2024-12-16这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&d);
printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day,day_of_year(d));
}
}
void test2() {
Date Alice_birth, Bob_birth;
int i;
int ans;
printf("输入Alice和Bob出生日期:(以形如2024-12-16这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&Alice_birth);
input(&Bob_birth);
ans = compare_dates(Alice_birth, Bob_birth);
if(ans == 0)
printf("Alice和Bob一样大\n\n");
else if(ans == -1)
printf("Alice比Bob大\n\n");
else
printf("Alice比Bob小\n\n");
}
}
int main() {
printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
test1();
printf("\n测试2: 两个人年龄大小关系\n");
test2();
system("pause");
return 0;
}
void input(Date *pd) {
char a='-',b='-';
scanf("%d %c %d %c %d",&pd->year,&a,&pd->month,&b,&pd->day);
}
int day_of_year(Date d) {
int sum = 0,b;
b = d.month - 1;
sum = (d.month-1)*30+d.day;
if(d.year%4==0){
while(b!=0){
if(b%2!=0){
sum++;
}
b--;
}
if(d.month>2){
sum--;
}
}
else{
while(b!=0){
if(b%2!=0){
sum++;
}
b--;
}
if(d.month>2){
sum-=2;
}
}
return sum;
}
int compare_dates(Date d1, Date d2) {
if(d1.year<d2.year){
return -1;
}
if(d1.year>d2.year){
return 1;
}
if(d1.year==d2.year){
if(d1.month<d2.month){
return -1;
}
if(d1.month>d2.month){
return 1;
}
if(d1.month==d2.month){
if(d1.day<d2.day){
return -1;
}
if(d1.day>d2.day){
return 1;
}
if(d1.day==d2.day){
return 0;
}
}
}
}
任务六
#include<stdlib.h>
#include <stdio.h>
#include <string.h>
enum Role {admin, student, teacher};
typedef struct {
char username[20];
char password[20];
enum Role type;
} Account;
void output(Account x[], int n);
int main() {
Account x[] = {
{"A1001", "123456", student},
{"A1002", "123abcdef", student},
{"A1009", "xyz12121", student},
{"X1009", "9213071x", admin},
{"C11553", "129dfg32k", teacher},
{"X3005", "921kfmg917", student}};
int n;
n = sizeof(x)/sizeof(Account);
output(x, n);
system("pause");
return 0;
}
void output(Account x[], int n) {
int i=0,b=0,k=0;
for(i=0;i<n;i++){
printf("%-30s",x[i].username);
b = strlen(x[i].password);
for(k=0;k<b;k++){
printf("*");
}
for(k=b;k<20;k++){
printf(" ");
}
switch(x[i].type){
case 0:
printf("admin\n");
break;
case 1:
printf("student\n");
break;
default:
printf("teacher\n");
break;
}
}
}
任务七
#include<stdlib.h>
#include <stdio.h>
#include <string.h>
typedef struct {
char name[20];
char phone[12];
int vip;
} Contact;
void set_vip_contact(Contact x[], int n, char name[]);
void output(Contact x[], int n);
void display(Contact x[], int n);
void sort(Contact x[],int n);
#define N 10
int main() {
Contact list[N] = {{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18853253914", 0},
{"李四", "13230584477", 0},
{"王五", "15547571923", 0},
{"赵六", "18856659351", 0},
{"周七", "17705843215", 0},
{"孙八", "15552933732", 0},
{"吴九", "18077702405", 0},
{"郑十", "18820725036", 0}};
int vip_cnt, i;
char name[20];
printf("显示原始通讯录信息: \n");
output(list, N);
printf("\n输入要设置的紧急联系人个数: ");
scanf("%d", &vip_cnt);
printf("输入%d个紧急联系人姓名:\n", vip_cnt);
for(i = 0; i < vip_cnt; ++i) {
scanf("%s", name);
set_vip_contact(list, N, name);
}
printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
display(list, N);
system("pause");
return 0;
}
void set_vip_contact(Contact x[], int n, char name[]) {
int i=0;
for(i=0;i<n;i++){
if(strcmp(x[i].name,name) == 0){
x[i].vip = 1;
}
}
}
void display(Contact x[], int n) {
sort(x,n);
int i=0;
for(i=0;i<n;i++){
if(x[i].vip == 1){
printf("%-10s%-30s*\n",x[i].name,x[i].phone);
}
}
for(i=0;i<n;i++){
if(x[i].vip == 0){
printf("%-10s%-30s\n",x[i].name,x[i].phone);
}
}
}
void output(Contact x[], int n) {
int i;
for(i = 0; i < n; ++i) {
printf("%-10s%-15s", x[i].name, x[i].phone);
if(x[i].vip)
printf("%5s", "*");
printf("\n");
}
}
void sort(Contact x[],int n){
Contact t;
int i=0,b=0;
for(i=0;i<n;i++){
for(b=0;b<n-1;b++){
if(strcmp(x[b].name,x[b+1].name)>0){
t = x[b];
x[b] = x[b+1];
x[b+1] = t;
}
}
}
标签：int,void,month,char,实验,printf,Date From： https://www.cnblogs.com/LittleZcy/p/18609278