问题描述
解题思路
只是1143.最长公共子序列的另一种描述
代码
#include <vector>
using std::vector;
class Solution {
public:
int maxUncrossedLines(vector<int> &nums1, vector<int> &nums2) {
vector<vector<int>> dp(nums1.size() + 1, vector<int>(nums2.size() + 1, 0));
for (int i = 1; i <= nums1.size(); i++) {
for (int j = 1; j <= nums2.size(); j++) {
if (nums1[i - 1] == nums2[j - 1])
dp[i][j] = max(max(dp[i - 1][j], dp[i][j - 1]), dp[i - 1][j - 1] + 1);
else
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);
}
}
return dp[nums1.size()][nums2.size()];
}
};
标签:uncrossed,int,lines,相交,vector,size,nums2,1035
From: https://www.cnblogs.com/zwyyy456/p/16841693.html