MISC01
某单位网络遭到非法的攻击，安全人员对流量调查取证之后保存了关键证据，发现人员的定位信息存在泄露，请对其进行分析。flag为用户位置信息进行32位md5哈希值
位置信息，所有我们开始试ip地址，试了一堆发现思路错误，4g通讯流量，直接问Chatgpt
MD5加密
MISC02
题目附件给了一个未知后缀的flag文件，是Ubuntu22.04的内存镜像，当时还不用allinone的vol，啊啊啊啊-_-...。
直接010，找到很多png形式的图片转base64
好多个位置表示的都是同一张图片
最终找到个有用图片，之前用foremost分离过，但是图片破损没有信息
提取出来
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
赛博厨子
图片不完整
缺少尾部信息，换种思路，寻找png的尾部信息
最终提取得到一下图
zsteg一下，查看图片lsb信息
有个掩码
回到镜像，找到了7z的压缩包
直接掩码爆破
值得注意的是aapr4.66以下的版本是不支持7z的压缩包的
打开压缩包
得到flag.txt
31 226 PUSH_NULL
228 LOAD_NAME 8 (key_encode)
230 LOAD_NAME 7 (key)
232 PRECALL 1
236 CALL 1
246 STORE_NAME 7 (key)
32 248 PUSH_NULL
250 LOAD_NAME 10 (len)
252 LOAD_NAME 7 (key)
254 PRECALL 1
258 CALL 1
268 LOAD_CONST 7 (16)
270 COMPARE_OP 2 (==)
276 POP_JUMP_FORWARD_IF_FALSE 43 (to 364)
33 278 PUSH_NULL
280 LOAD_NAME 9 (sm4_encode)
282 LOAD_NAME 7 (key)
284 LOAD_NAME 5 (flag)
286 PRECALL 2
290 CALL 2
300 LOAD_METHOD 11 (hex)
322 PRECALL 0
326 CALL 0
336 STORE_NAME 12 (encrypted_data)
34 338 PUSH_NULL
340 LOAD_NAME 6 (print)
342 LOAD_NAME 12 (encrypted_data)
344 PRECALL 1
348 CALL 1
358 POP_TOP
360 LOAD_CONST 2 (None)
362 RETURN_VALUE
32 >> 364 LOAD_CONST 2 (None)
366 RETURN_VALUE
Disassembly of <code object key_encode at 0x14e048a00, file "make.py", line 10>:
10 0 RESUME 0
11 2 LOAD_GLOBAL 1 (NULL + list)
14 LOAD_FAST 0 (key)
16 PRECALL 1
20 CALL 1
30 STORE_FAST 1 (magic_key)
12 32 LOAD_GLOBAL 3 (NULL + range)
44 LOAD_CONST 1 (1)
46 LOAD_GLOBAL 5 (NULL + len)
58 LOAD_FAST 1 (magic_key)
60 PRECALL 1
64 CALL 1
74 PRECALL 2
78 CALL 2
88 GET_ITER
>> 90 FOR_ITER 105 (to 302)
92 STORE_FAST 2 (i)
13 94 LOAD_GLOBAL 7 (NULL + str)
106 LOAD_GLOBAL 9 (NULL + hex)
118 LOAD_GLOBAL 11 (NULL + int)
130 LOAD_CONST 2 ('0x')
132 LOAD_FAST 1 (magic_key)
134 LOAD_FAST 2 (i)
136 BINARY_SUBSCR
146 BINARY_OP 0 (+)
150 LOAD_CONST 3 (16)
152 PRECALL 2
156 CALL 2
166 LOAD_GLOBAL 11 (NULL + int)
178 LOAD_CONST 2 ('0x')
180 LOAD_FAST 1 (magic_key)
182 LOAD_FAST 2 (i)
184 LOAD_CONST 1 (1)
186 BINARY_OP 10 (-)
190 BINARY_SUBSCR
200 BINARY_OP 0 (+)
204 LOAD_CONST 3 (16)
206 PRECALL 2
210 CALL 2
220 BINARY_OP 12 (^)
224 PRECALL 1
228 CALL 1
238 PRECALL 1
242 CALL 1
252 LOAD_METHOD 6 (replace)
274 LOAD_CONST 2 ('0x')
276 LOAD_CONST 4 ('')
278 PRECALL 2
282 CALL 2
292 LOAD_FAST 1 (magic_key)
294 LOAD_FAST 2 (i)
296 STORE_SUBSCR
300 JUMP_BACKWARD 106 (to 90)
15 >> 302 LOAD_GLOBAL 3 (NULL + range)
314 LOAD_CONST 5 (0)
316 LOAD_GLOBAL 5 (NULL + len)
328 LOAD_FAST 0 (key)
330 PRECALL 1
334 CALL 1
344 LOAD_CONST 6 (2)
346 PRECALL 3
350 CALL 3
360 GET_ITER
>> 362 FOR_ITER 105 (to 574)
364 STORE_FAST 2 (i)
16 366 LOAD_GLOBAL 7 (NULL + str)
378 LOAD_GLOBAL 9 (NULL + hex)
390 LOAD_GLOBAL 11 (NULL + int)
402 LOAD_CONST 2 ('0x')
404 LOAD_FAST 1 (magic_key)
406 LOAD_FAST 2 (i)
408 BINARY_SUBSCR
418 BINARY_OP 0 (+)
422 LOAD_CONST 3 (16)
424 PRECALL 2
428 CALL 2
438 LOAD_GLOBAL 11 (NULL + int)
450 LOAD_CONST 2 ('0x')
452 LOAD_FAST 1 (magic_key)
454 LOAD_FAST 2 (i)
456 LOAD_CONST 1 (1)
458 BINARY_OP 0 (+)
462 BINARY_SUBSCR
472 BINARY_OP 0 (+)
476 LOAD_CONST 3 (16)
478 PRECALL 2
482 CALL 2
492 BINARY_OP 12 (^)
496 PRECALL 1
500 CALL 1
510 PRECALL 1
514 CALL 1
524 LOAD_METHOD 6 (replace)
546 LOAD_CONST 2 ('0x')
548 LOAD_CONST 4 ('')
550 PRECALL 2
554 CALL 2
564 LOAD_FAST 1 (magic_key)
566 LOAD_FAST 2 (i)
568 STORE_SUBSCR
572 JUMP_BACKWARD 106 (to 362)
18 >> 574 LOAD_CONST 4 ('')
576 LOAD_METHOD 7 (join)
598 LOAD_FAST 1 (magic_key)
600 PRECALL 1
604 CALL 1
614 STORE_FAST 1 (magic_key)
19 616 LOAD_GLOBAL 17 (NULL + print)
628 LOAD_FAST 1 (magic_key)
630 PRECALL 1
634 CALL 1
644 POP_TOP
20 646 LOAD_GLOBAL 7 (NULL + str)
658 LOAD_GLOBAL 9 (NULL + hex)
670 LOAD_GLOBAL 11 (NULL + int)
682 LOAD_CONST 2 ('0x')
684 LOAD_FAST 1 (magic_key)
686 BINARY_OP 0 (+)
690 LOAD_CONST 3 (16)
692 PRECALL 2
696 CALL 2
706 LOAD_GLOBAL 11 (NULL + int)
718 LOAD_CONST 2 ('0x')
720 LOAD_FAST 0 (key)
722 BINARY_OP 0 (+)
726 LOAD_CONST 3 (16)
728 PRECALL 2
732 CALL 2
742 BINARY_OP 12 (^)
746 PRECALL 1
750 CALL 1
760 PRECALL 1
764 CALL 1
774 LOAD_METHOD 6 (replace)
796 LOAD_CONST 2 ('0x')
798 LOAD_CONST 4 ('')
800 PRECALL 2
804 CALL 2
814 STORE_FAST 3 (wdb_key)
21 816 LOAD_GLOBAL 17 (NULL + print)
828 LOAD_FAST 3 (wdb_key)
830 PRECALL 1
834 CALL 1
844 POP_TOP
22 846 LOAD_FAST 3 (wdb_key)
848 RETURN_VALUE
magic_key:5afe22e113aa05ae
encrypted_data:128ae9d850aa394bc1e13eb785f3a2049ef260011195b3f54ebdf23e550eb0ce0d46e1d99b312fd8975f91dc70ba03c5
python的字节码，内容是加密了密钥然后用SM4算法加密了flag,用下Lunatic神的手搓脚本
def restore(mk):
magic_key = [_ for _ in mk]
for i in range(0, len(mk), 2):
magic_key[i] = hex(int("0x" + magic_key[i], 16) ^ int("0x" + magic_key[i + 1], 16)).replace("0x", "")
for i in range(len(mk) - 1, 0, -1):
magic_key[i] = hex(int("0x" + magic_key[i], 16) ^ int("0x" + magic_key[i - 1], 16)).replace("0x", "")
return "".join(magic_key)
def encode_key(key):
magic_key = [_ for _ in key]
for i in range(1, len(key)):
magic_key[i] = hex(int("0x" + magic_key[i], 16) ^ int("0x" + magic_key[i - 1], 16)).replace("0x", "")
for i in range(0, len(key), 2):
magic_key[i] = hex(int("0x" + magic_key[i], 16) ^ int("0x" + magic_key[i + 1], 16)).replace("0x", "")
magic_key = "".join(magic_key)
wdb_key = hex(int("0x" + magic_key, 16) ^ int("0x" + key, 16)).replace("0x", "")
return wdb_key
print(encode_key(restore("5afe22e113aa05ae")))
最后CyberChef解一个SM4即可得到flag
MISC03
近日某公司服务器遭到恶意攻击，随后公司立即对流量监测系统中遭受攻击时段的流量进行了取证，但是公司某一网络安全实习生进行分析溯源后并未找到攻击者的攻击IP，于是公司决定将这个任务重新交给更具经验的你来进行，接手工作后，你立即对其进行了深入调查！
好入手，直接爆破出所有IP即可
from scapy.all import rdpcap
def extract_ip_related_info(file_path):
# 读取.pcap文件
packets = rdpcap(file_path)
# 使用集合存储唯一的与IP相关的信息
ip_info_set = set()
for packet in packets:
# 检查是否是IP包
if packet.haslayer('IP'):
ip_src = packet['IP'].src
ip_dst = packet['IP'].dst
flags = packet['IP'].flags
# 将源IP和目标IP添加到集合中
ip_info_set.add(f"Source IP: {ip_src}")
ip_info_set.add(f"Destination IP: {ip_dst}")
ip_info_set.add(f"Flags: {flags}") # 如果需要其他IP层字段，可以添加更多
# 检查是否有其他与IP相关的字段
# 例如：协议类型
protocol = packet['IP'].proto
ip_info_set.add(f"Protocol: {protocol}")
# 输出唯一的与IP相关的信息
print("提取到的与IP相关的唯一信息:")
for info in ip_info_set:
print(info)
# 调用函数并传入.pcap文件路径
extract_ip_related_info(r'C:\Users\Lenovo\Desktop\c.pcap')
第一个就是flag呢
MISC04
某测试人员刚刚完成了一款图像加密算法的开发，想要邀请你进行深入的分析测试。
参考irisctf2024 The Peano Scramble
https://zhuanlan.zhihu.com/p/305623626<----peano搜索发现是一种分形几何
from PIL import Image
from tqdm import tqdm
def peano(n):
if n == 0:
return [[0,0]]
else:
in_lst = peano(n - 1)
lst = in_lst.copy()
px,py = lst[-1]
lst.extend([px - i[0], py + 1 + i[1]] for i in in_lst)
px,py = lst[-1]
lst.extend([px + i[0], py + 1 + i[1]] for i in in_lst)
px,py = lst[-1]
lst.extend([px + 1 + i[0], py - i[1]] for i in in_lst)
px,py = lst[-1]
lst.extend([px - i[0], py - 1 - i[1]] for i in in_lst)
px,py = lst[-1]
lst.extend([px + i[0], py - 1 - i[1]] for i in in_lst)
px,py = lst[-1]
lst.extend([px + 1 + i[0], py + i[1]] for i in in_lst)
px,py = lst[-1]
lst.extend([px - i[0], py + 1 + i[1]] for i in in_lst)
px,py = lst[-1]
lst.extend([px + i[0], py + 1 + i[1]] for i in in_lst)
return lst
order = peano(6)
img = Image.open(r"C:\Users\Lenovo\Desktop\1.png")
width, height = img.size
block_width = width # // 3
block_height = height # // 3
new_image = Image.new("RGB", (width, height))
for i, (x, y) in tqdm(enumerate(order)):
# 根据列表顺序获取新的坐标
new_x, new_y = i % width, i // width
# 获取原图像素
pixel = img.getpixel((x, height - 1 - y))
# 在新图像中放置像素
new_image.putpixel((new_x, new_y), pixel)
new_image.save("rearranged_image.jpg")
恢复二维码扫码即可。
标签：LOAD,magic,Misc,2024,lst,CALL,key,PRECALL,网鼎杯 From： https://www.cnblogs.com/alexander17/p/18551685