小数高精度乘法
m*(1+r/100)^y
Program P2390;
const
maxn=40000;
F=10;
type
arr=record
d:array[1..maxn] of longint;
len,doc:longint;
end;
var
r,m:arr;
y:longint;
i:longint;
a,b:arr;
function max(a,b:longint):longint;
begin
if a<b then exit(b) else exit(a);
end;
procedure multipy(a,b:arr;var c:arr);
var
i,j,len:longint;
begin
fillchar(c,sizeof(c),0);
c.len:=a.len+b.len;
for i:=1 to a.len do
for j:=1 to b.len do
begin
inc(c.d[i+j-1],a.d[i]*b.d[j]);
inc(c.d[i+j],c.d[i+j-1] div F);
c.d[i+j-1]:=c.d[i+j-1] mod F;
end;
while (c.d[c.len]=0) and (c.len>1) do dec(c.len);
c.doc:=a.doc+b.doc;
end;
procedure to_arr(doc:longint;var c:arr);
var
x,i,n:longint;
begin
read(x);
i:=0;
while (x>0) do
begin
inc(i);
c.d[i]:=x mod F;
x:=x div F;
end;
c.len:=i;
c.doc:=doc;
end;
Procedure jie(a:arr;x:longint;var c:arr);
begin
if x=1 then begin c:=a; exit; end;
fillchar(c,sizeof(c),0);
if (x mod 2=0) then
begin
jie(a,x div 2,c);
multipy(c,c,c);
end
else
begin
jie(a,x div 2,c);
multipy(c,c,c);
multipy(a,c,c);
end;
end;
begin
to_arr(2,r);
r.len:=3;r.d[3]:=1;
to_arr(0,m);
read(y);
jie(r,y,r);
multipy(m,r,m);
for i:=m.len downto m.doc+1 do write(m.d[i]);
writeln;
end.