Valid Anagram
Given two strings s and t, return true if t is an anagram of s, and false otherwise.
An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.
Example 1:
Input: s = "anagram", t = "nagaram"
Output: true
Example 2:
Input: s = "rat", t = "car"
Output: false
Constraints:
1 <= s.length, t.length <= 5 * 104
s and t consist of lowercase English letters.
Follow up: What if the inputs contain Unicode characters? How would you adapt your solution to such a case?
思路一: 刚开始想到用 xor 位运算,不过这题不能用。然后就是 map 的思路,记录字符出现的次数
public boolean isAnagram(String s, String t) {
if (s.length() != t.length()) return false;
int[] count = new int[26];
for (int i = 0; i < s.length(); i++) {
count[s.charAt(i) - 'a']++;
count[t.charAt(i) - 'a']--;
}
for (int i : count) {
if (i != 0) return false;
}
return true;
}
标签:count,false,int,length,easy,242,return,true,leetcode
From: https://www.cnblogs.com/iyiluo/p/16818372.html